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Anarel [89]
3 years ago
7

there are 20 total students in Kim's class. 12 of the students are boys and 8 are girls. which of the following reqesents the pa

rt of the class that is boys​
Mathematics
1 answer:
diamong [38]3 years ago
3 0

Answer:

Step-by-step explanation:

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Determine any data values that are missing from the table, assuming that the data represent a linear function.
AleksAgata [21]

Answer:

c

Step-by-step explanation:

3 0
3 years ago
Assortative mating is a nonrandom mating pattern where individuals with similar genotypes and/or phenotypes mate with one anothe
scZoUnD [109]

Answer:

a) P(male=blue or female=blue) = 0.71

b) P(female=blue | male=blue) = 0.68

c) P(female=blue | male=brown) = 0.35

d) P(female=blue | male=green) = 0.31

e) We can conclude that the eye colors of male respondents and their partners are not independent.

Step-by-step explanation:

We are given following information about eye colors of 204 Scandinavian men and their female partners.

              Blue    Brown     Green    Total

Blue        78         23            13          114

Brown     19         23            12          54

Green     11           9             16          36

Total      108       55            41          204

a) What is the probability that a randomly chosen male respondent or his partner has blue eyes?

Using the addition rule of probability,

∵ P(A or B) = P(A) + P(B) - P(A and B)

For the given case,

P(male=blue or female=blue) = P(male=blue) + P(female=blue) - P(male=blue and female=blue)

P(male=blue or female=blue) = 114/204 + 108/204 − 78/204

P(male=blue or female=blue) = 0.71

b) What is the probability that a randomly chosen male respondent with blue eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=blue) = 78/114

P(female=blue | male=blue) = 0.68

c) What is the probability that a randomly chosen male respondent with brown eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=brown) = 19/54

P(female=blue | male=brown) = 0.35

d) What is the probability of a randomly chosen male respondent with green eyes having a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=green) = 11/36

P(female=blue | male=green) = 0.31

e) Does it appear that the eye colors of male respondents and their partners are independent? Explain

If the following relation holds true then we can conclude that the eye colors of male respondents and their partners are independent.

∵ P(B | A) = P(B)

P(female=blue | male=brown) = P(female=blue)

or alternatively, you can also test

P(female=blue | male=green) = P(female=blue)

P(female=blue | male=blue) = P(female=blue)

But

P(female=blue | male=brown) ≠ P(female=blue)

19/54 ≠ 108/204

0.35 ≠ 0.53

Therefore, we can conclude that the eye colors of male respondents and their partners are not independent.

7 0
3 years ago
21. Mickey earned $475 from mowing lawns last summer. He deposited this money in an
Dennis_Churaev [7]

Answer:

first, u need to know the formula for compound interest, which is:

A = P(1 + \frac{r}{100})^{n}

where A is the final amount

P- initial amount

r- percent compounded(interest)

and

n- number of years

so

we have

A = 475(1 + \frac{3.8}{100})^{4}

3.8/100 = 0.038

1+0.038 =1.038

1.038^4 = 1.160885573136

475 * 1.160885573136 = 551.4206472396‬

approximately $551.42

5 0
4 years ago
In the base 5 number system, which number comes after 444,444?
RSB [31]
I think it’s 555,555






3 0
3 years ago
Convert 11.42424242 … to a rational expression in the form of a over b, where b ≠ 0.
Pavlova-9 [17]

x=11.4242....

100x=1142.4242....

100x-x = 99x = 1131

x=1131/99 = 11 42/99 (unreduced) = 11 14/33 (reduced fraction)

7 0
3 years ago
Read 2 more answers
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