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Viktor [21]
2 years ago
7

What is the measure of <3

Mathematics
1 answer:
Marat540 [252]2 years ago
6 0

Answer:

love sucks

Step-by-step explanation:

love sucks

love sucks sucks

love sucks sucks sucks

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What is the height of the cone below?<br><br> V = 45 in^3<br><br> B = 5in^2
Lapatulllka [165]

Answer:

The height of the cone is h = 27

Step-by-step explanation:

<u>Formula:</u>-

Step 1:-

The volume of the cone is  V=\frac{1}{3} (base)(height)

Given volume is V= 45 in^ 3

Given base of the cone is B= 5 in^2

<u>Step 2</u>:-

by using formula, we get solution

45 = \frac{1}{3} (5)(h)

cross multiplication, we get

\frac{45 x 3}{5} =h

now simplification, the height of the cone is h = 27

7 0
3 years ago
Easy 6th grade math! Please help!
Pie

Answer:

Step-by-step explanation 10 + 2.50d = 850

David starts with $10 and each day he earns $2.50. The d represents a variable and can be any number.

To find d you must solve the equation.

10 + 2.50d = 850

2.50d = 840 (subtract 10 from 850)

d = 336 (divide 840 by 2.50)

It will take David 336 days to save $850.

3 0
3 years ago
Suppose you pay $1.00 to roll a fair die with the understanding you will get $3.00 back rolling a 4 or a 2, and nothing otherwis
nikdorinn [45]

There are 2 chances out of 6 to win $3

Every 6 rolls you are expected to win $6

Every 3 rolls you are expected to win $3.

On average, even though it's impossible, every roll you would make $1.

6 0
2 years ago
4. Write the equation in standard form: y=3/4x – 6
wariber [46]
Y=3x/4-6

doing this is thinking of it in a matter of geometric figure and how you would plot it on a graph and this is the only way it would look write.
7 0
3 years ago
Suppose we want to build a rectangular storage container with open top whose volume is $$12 cubic meters. Assume that the cost o
Snezhnost [94]

Answer:265.25

Step-by-step explanation:

Given

Volume of box=12 m^3

height is 3 times the width

let height, length and breadth be H, L & B

H=3\times B

V=12=L\times B\times H

4=B^2\times L[/tex]

L=\frac{4}{B^2}

Cost of side walls $ 8/m^2

Cost of base $ 12/m^2

Cost of side walls=(2LH+2BH)\cdot 8

Cost of base =12LB

Total cost C=16LH+16BH+12LB

C=48LB+48B^2+12LB

C=\frac{192}{B}+48B^2+\frac{48}{B}

differentiate C w.r.t B to get minimum cost

\frac{\mathrm{d} C}{\mathrm{d} B}=-\frac{192}{B^2}+2\times 48 B-\frac{48}{B^2}

B^3=\frac{240}{2\times 48}

B=1.35 m

H=3\times 1.35=4.07 m

L=2.19 m

C=$ 265.25

3 0
2 years ago
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