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k0ka [10]
3 years ago
11

What is the mean for the data set?

Mathematics
1 answer:
myrzilka [38]3 years ago
6 0

Answer:

14

Step-by-step explanation:

you add up all the numbers and divide that by the amount of numbers there. 69/5=13.8 ~ 14

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nasty-shy [4]
I would choose D and C

Hope this Helps!!!!
7 0
3 years ago
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Find the x intercepts of the parabola with vertex (-1,-16) and y intercept (0,-15)
balandron [24]
<span> first, write the equation of the parabola in the required form: </span>
<span>(y - k) = a·(x - h)² </span>

<span>Here, (h, k) is given as (-1, -16). </span>
<span>So you have: </span>
<span>(y + 16) = a · (x + 1)² </span>

<span>Unfortunately, a is not given. However, you do know one additional point on the parabola: (0, -15): </span>

<span>-15 + 16 = a· (0 + 1)² </span>
<span>.·. a = 1 </span>

<span>.·. the equation of the parabola in vertex form is </span>
<span>y + 16 = (x + 1)² </span>

<span>The x-intercepts are the values of x that make y = 0. So, let y = 0: </span>

<span>0 + 16 = (x + 1)² </span>
<span>16 = (x + 1)² </span>

<span>We are trying to solve for x, so take the square root of both sides - but be CAREFUL! </span>

<span>± 4 = x + 1 ...... remember both the positive and negative roots of 16...... </span>

<span>Solving for x: </span>
<span>x = -1 + 4, x = -1 - 4 </span>
<span>x = 3, x = -5. </span>

<span>Or, if you prefer, (3, 0), (-5, 0). </span>
8 0
3 years ago
Find the value of x in the<br> isosceles triangle shown below.<br> Help plzzzz
zysi [14]

Answer:

x =2

Option D is correct !!!

Step-by-step explanation:

By Pythagoras theorem we can solve this

we know that:

{x}^{2}  +  {4}^{2}  =  \sqrt{20} {}^{2}

{x}^{2}  =  \sqrt{20} ^{2}   - 16

{x}^{2} = 20 - 16

x = 2

6 0
4 years ago
What is an explicit equation?
artcher [175]
An explicit equation is an equation used to find a term in a sequence without using the any previous terms. For example, if I have the set of numbers 1, 3, 5, 7, 9, my explicit equation is F(n)=2(n-1)+1. If I plug 1 in for n, I get F(1)= 2(0)+1, which is 1, my first term.

Hope this made sense.
4 0
4 years ago
Use the Divergence Theorem to compute the net outward flux of the field F=&lt;-2x,y,-2z&gt; across the surface S, where S is the
lutik1710 [3]

Answer:

The net outward flux across the boundary of the tetrahedron is: -4

Step-by-step explanation:

Given vector field F = ( -2x, y, - 2 z )

div F = \nabla F = ( i \dfrac{\partial }{\partial x }+ j \dfrac{\partial}{\partial y} + k \dfrac{\partial}{\partial z}) \langle -2x, y, -2z \rangle

div F = \nabla F = ( \dfrac{\partial }{\partial x }(-2x)+  \dfrac{\partial}{\partial y}(y) + \dfrac{\partial}{\partial z}(-2z))

= -2 + 1 -2

= -3

According to divergence theorem;

Flux = \int \int \int div \ \ (F) \ dv

x+y+z = 2; 1^{st}  Octant

x from 0 to 2

y from 0 to 2 -x

z from 0 to 2-x-y

= \int\limits^2_0 \int\limits^{2-x}_0 \int\limits^{2-x-y}_0 -3dzdydx

=-3 \int\limits^2_0 \int\limits^{2-x}_0 (2-x-y)dy dx

= -3 \int\limits^2_0[(2-x)y - \dfrac{y^2}{2}]^{2-x}__0 \ \ dx

= -3 \int\limits^2_0(2-x)^2 - \dfrac{(2-x)^2}{2} dx

= -3 \int\limits^2_0\dfrac{(2-x)^2}{2} dx = - \dfrac{3}{2} \int\limits^2_0(4-4x+x^2) dx

=- \dfrac{3}{2}(4x-x^2 + \dfrac{x^3}{3})^2_0

=- \dfrac{3}{2}(8-8+\dfrac{8}{3})

=- \dfrac{3}{2}(\dfrac{8}{3})

= -4

Thus; The net outward flux across the boundary of the tetrahedron is: -4

3 0
4 years ago
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