So it would be x12 to the 2nd power, kinda hard to explain but i really hope this helped
Answer:
Linear. While all linear equations produce straight lines when graphed, not all linear equations produce linear functions. In order to be a linear function, a graph must be both linear (a straight line) and a function (matching each x-value to only one y-value).
Parameterize ![S{/tex] by[tex]\vec s(u,v)=u\,\vec\imath+v\,\vec\jmath+(8-u^2-v^2)\,\vec k](https://tex.z-dn.net/?f=S%7B%2Ftex%5D%20by%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Cvec%20s%28u%2Cv%29%3Du%5C%2C%5Cvec%5Cimath%2Bv%5C%2C%5Cvec%5Cjmath%2B%288-u%5E2-v%5E2%29%5C%2C%5Cvec%20k)
with 
and 
.
Take the normal vector to 
to be
Then the flux of 
across is
Answer:
15 boys
Step-by-step explanation:
There are 27 students. The number of girls is only 4/5 of the number of boys. I started by splitting the class. 14 boys and 13 girls doesn't work, so I changed it to 12 and 15. If it was 12 girls and 15 boys, the girls would have 4/5 of the boys, so it must be 12 girls and 15 boys.
