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3 years ago

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The measure of the exterior angle at one base angle of an isosceles triangle is 125 degrees. what is the measure of the vertex a

ngle in degree the measure of the exterior angle at one base angle of an isosceles triangle is 125 degrees. what is the measure of the vertex angle in degrees

2 answers:

Yanka [14]3 years ago

5 0

Attached the solution and work. I think this is what you asked for.

2 years ago

https://answer.ya.guru/media/im/ab9/ef/ab9efe430841c33d5db59d504b7b482e.jpg

2 years ago

gotcha back

yarga [219]3 years ago

5 0

Answer:

55 degrees

Step-by-step explanation:

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2 years ago

this week maddie worked 2 1/2 hours on monday, 2 2/3 hours on tuesday and 3 1/4 hours on wednesday. how many more hours will mad

ddd [48]

For this you will have to know how to add fractions. First of all i like to add the whole numbers together first, so 2+2+3= 7. so now what you have to do is add the fractions together. so 2/3 + 1/4 + 1/2 = ? you will have to find a common denominator for 3, 4, and 2; which is 12. Multiply each fraction by the needed number to get each denominator to 12. so 2/3 will be multiplied by 4, 1/4 will be multiplied by 3, and 1/2 will be multiplied by 6. The new equation and answer will be: 8/12 + 3/12 + 6/12 = 17/12. 17/12 as a mixed fraction is 1 5/12. now we add 1 5/12 and 7 to equal 8 5/12. and then you will have to subtract this from 10, using common denominators and such to get your final answer of 2 1/12. (sorry for the long spiel on how to do this question)

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3 years ago

Drag the tiles to the correct boxes to complete the pairs.

Mashcka [7]

Answer:

Part 1) $-17\frac{8}{9}$ -----> $-6\frac{4}{9}-3\frac{2}{9}-8\frac{2}{9}$

Part 2) $-15.11$ ------> $-12.48-(-2.99)-5.62$

Part 3) $-19\frac{8}{9}$ -----> $-19\frac{2}{9}-4\frac{1}{9}-(-3\frac{4}{9})$

Part 4) $-201.65$ -----> $-353.92-(-283.56)-131.29$

Part 5) $74$ ------> $83\frac{1}{5}-108\frac{2}{5}-(-99\frac{1}{5})$

Step-by-step explanation:

Part 1) we have

$-6\frac{4}{9}-3\frac{2}{9}-8\frac{2}{9}$

To calculate the subtraction convert the mixed numbers to an improper fractions

$6\frac{4}{9}=\frac{6*9+4}{9}=\frac{58}{9}$

$3\frac{2}{9}=\frac{3*9+2}{9}=\frac{29}{9}$

$8\frac{2}{9}=\frac{8*9+2}{9}=\frac{74}{9}$

substitute

$-\frac{58}{9}-\frac{29}{9}-\frac{74}{9}=-\frac{(58+29+74)}{9}=-\frac{161}{9}$

Convert to mixed number

$-\frac{161}{9}=-(\frac{153}{9}+\frac{8}{9})=-17\frac{8}{9}$

Part 2) we have

$-12.48-(-2.99)-5.62$

To calculate the subtraction eliminate the parenthesis first

$-12.48-(-2.99)-5.62=-12.48+2.99-5.62=-15.11$

Part 3) we have

$-19\frac{2}{9}-4\frac{1}{9}-(-3\frac{4}{9})$

To calculate the subtraction convert the mixed numbers to an improper fractions

$19\frac{2}{9}=\frac{19*9+2}{9}=\frac{173}{9}$

$4\frac{1}{9}=\frac{4*9+1}{9}=\frac{37}{9}$

$3\frac{4}{9}=\frac{3*9+4}{9}=\frac{31}{9}$

substitute

$-\frac{173}{9}-\frac{37}{9}-(-\frac{31}{9})$

Eliminate the parenthesis

$-\frac{173}{9}-\frac{37}{9}+\frac{31}{9}=\frac{(-173-37+31)}{9}=-\frac{179}{9}$

Convert to mixed number

$-\frac{179}{9}=-(\frac{171}{9}+\frac{8}{9})=-19\frac{8}{9}$

Part 4) we have

$-353.92-(-283.56)-131.29$

To calculate the subtraction eliminate the parenthesis first

$-353.92+283.56-131.29=-201.65$

Part 5) we have

$83\frac{1}{5}-108\frac{2}{5}-(-99\frac{1}{5})$

To calculate the subtraction convert the mixed numbers to an improper fractions

$83\frac{1}{5}=\frac{83*5+1}{5}=\frac{416}{5}$

$108\frac{2}{5}=\frac{108*5+2}{5}=\frac{542}{5}$

$99\frac{1}{5}=\frac{99*5+1}{5}=\frac{496}{5}$

substitute

$\frac{416}{5}-\frac{542}{5}-(-\frac{496}{5})$

Eliminate the parenthesis

$\frac{416}{5}-\frac{542}{5}+\frac{496}{5}=\frac{(416-542+496)}{5}=\frac{370}{5}=74$

3 0

3 years ago