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My name is Ann [436]
3 years ago
10

Solve the following system of equations by substitution. please explain y=-2x+1 3x-2y=5

Mathematics
1 answer:
s2008m [1.1K]3 years ago
7 0

Answer:

x=1

Step-by-step explanation:

y= -2x+1\\3x-2y=5

You substitute -2x+1 for y in the second equation, because it is equal to y.

3x-2(-2x+1)=5\\3x-(-4x+2)=5\\3x+4x-2=5\\7x-2=5\\7x=7\\x=1

Alternate Method:

set both equations equal to y

3x-2y=5\\3x-5=2y\\y=\frac{3x-5}{2}

Then you have

y=-2x+1\\y=\frac{3x-5}{2}

And you substitute one of the equations in for y in the other one

-2x+1=\frac{3x-5}{2} \\

multiply both sides by 2

-4x+2=3x-5

and solve

7x=7\\x=1

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Help me with number 10 pleaseeeeeeeeee
valina [46]

Answer:

4' - 9.64

Step-by-step explanation:

Total rise = 2' - 7"

Total run = 3' - 9"

Converting to inches :

1' = 12" ; 1 feet = 12 inches

2' = 2 * 12 = 24"

3' = 3 * 12 = 36"

Total rise = 24" + 7" = 31"

Total run = 36" + 9" = 45"

Length of stringer = hypotenus

Hypotenus = √(total rise² + total run²)

Hypotenus = √(31² + 45²)

Hypotenus = 54.644304"

= 4' - 9.64"

6 0
3 years ago
why write a quadratic function whose graph has the given characteristics vertex :(2,3) point on graph (0,-1)
GaryK [48]
<h3>Answer:</h3>

f(x) = -(x -2)² +3

<h3>Step-by-step explanation:</h3>

We can fill in the vertex (h, k) values immediately in the vertex form ...

... f(x) = a(x -h)² +k

To find the value of a, we solve the equation for a at some point other than the vertex. The given point is (0, -1), so we can use that:

... -1 = a(0 -2)² +3

... -4 = 4a . . . . . . . . . subtract 3, simplify

... -1 = a . . . . . . . . . . . divide by 4

Now, we know the function is ...

... f(x) = -(x -2)² +3

5 0
3 years ago
How many different groups of 6 shirts can be formed from 10 shirts for a display
Margarita [4]
I believe the shirts are different (in color, in size, in style,...), is so then:

¹⁰C₆ = (10! )/( 6! )( 10-6) ! = 210 COMBBINATIONS
6 0
4 years ago
Read 2 more answers
HELP ASAP Calculate the residuals for your scatterplot in step 2d.
postnew [5]

The residuals of the linear regression equation are -1.36, 0.32, 0.01, 0.62, 0.17, -0.24, 0.89, 0.09, 0.18 and -0.7

<h3>How to determine the residuals?</h3>

The regression equation is given as:

y = 0.141x + 0.842

Next, we calculate the predicted values (y) at the corresponding x values.

So, we have:

y = 0.141 * 13.8 + 0.842 = 2.78

y = 0.141 * 18 + 0.842 = 3.38

y = 0.141 * 16.7 + 0.842 = 3.20

y = 0.141 * 18 + 0.842 = 3.38

y = 0.141 * 0.7 + 0.842 = 0.94

y = 0.141 * 21.9 + 0.842 = 3.93

y = 0.141 * 15.5 + 0.842 = 3.03

y = 0.141 * 9.2 + 0.842 = 2.14

y = 0.141 * 19.5 + 0.842 = 3.59

y = 0.141 * 16.7 + 0.842 = 3.20

The residuals are then calculated using:

Residual = Actual value - Predicted value

So, we have:

Residual = 1.42 - 2.78 = -1.36

Residual = 3.7 - 3.38 = 0.32

Residual = 3.21 - 3.20 = 0.01

Residual = 4 - 3.38 = 0.62

Residual = 1.11 - 0.94 = 0.17

Residual = 3.69 - 3.93 = -0.24

Residual = 3.92 - 3.03 = 0.89

Residual = 2.23 - 2.14 = 0.09

Residual = 3.77 - 3.59 = 0.18

Residual = 2.5 - 3.20 = -0.7

Hence, the residuals of the linear regression equation are -1.36, 0.32, 0.01, 0.62, 0.17, -0.24, 0.89, 0.09, 0.18 and -0.7

Read more about residuals at:

brainly.com/question/16180255

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2 years ago
What is 283+t 748-235+7493-7
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Answer:

t^748+7534

Step-by-step explanation:


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