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Anvisha [2.4K]
3 years ago
6

HELP !! HELP ME PLEASE WITH THESE 3 PROBLEMS !!!!25 POINTS !!!

Mathematics
1 answer:
Anastasy [175]3 years ago
7 0
4)

\bf \cfrac{model}{tower}\qquad \cfrac{2}{25}=\cfrac{m}{160}

solve for "m"

5)

\bf \textit{sprinkle park to parking lot}\quad \cfrac{drawing}{park}\qquad \cfrac{15}{60}\implies \cfrac{1}{4}
\\\\\\
\textit{playground to sprinkle park}\qquad \cfrac{drawing}{park}\qquad \cfrac{1}{4}=\cfrac{12}{p}

solve for "p"

6)

\bf \begin{array}{ccllll}
cake&people\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1&18\\
x&108
\end{array}\implies \cfrac{1}{x}=\cfrac{18 }{108}

solve for "x".
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Multiple choices answer and explain the solution?
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Answer:

associative property of multiplication

Step-by-step explanation:

You cant rlly explain, you just have to know your properties

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3 years ago
I'm confused about this question
lesantik [10]

Answer:

the answer is 3

Step-by-step explanation:

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3 years ago
Help please.<br><br><br><br> Thank you.
Tom [10]

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A,D,C would be your answers

Step-by-step explanation:

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Read 2 more answers
How many solutions are there to the equation below?<br> 8x + 47 = 8(x + 5)
qaws [65]

Answer:

there are 0 solutions to the equation

Step-by-step explanation:

To know how many solutions are in the problem, we have to solve for x and see what result we have left. According to the result, we will know how many solutions there are

8x + 47 = 8(x + 5)

8x + 47 = 8*x + 8*5

8x + 47 = 8x + 40

8x - 8x = 40 - 47

0 = -7

As we can see we are left with an equality that is not fulfilled, this means that there is no solution to the problem, at least in the field of real numbers

4 0
2 years ago
Simplify.Your answer should contain only positive exponents.
zhannawk [14.2K]

Step-by-step explanation:

1) r^3r^3

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

=r^{3+3}

=r^6

2) 3k^3k^3

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

=3k^{3+3}

=3k^6

3) \left(3b^2\right)^3

\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n

=3^3\left(b^2\right)^3

=27\left(b^2\right)^3

=27b^6

4) \left(2m^3\right)^3

\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n

=2^3\left(m^3\right)^3

=8\left(m^3\right)^3

=8m^{3\cdot \:3}

=8m^9

5) \frac{3r^3}{r^2}

\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}

=3r^{3-2}

=3r^1

=3r

3 0
2 years ago
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