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3 years ago

HELP !! HELP ME PLEASE WITH THESE 3 PROBLEMS !!!!25 POINTS !!!

Mathematics

1 answer:

Anastasy [175]3 years ago

7 0

4)

$\bf \cfrac{model}{tower}\qquad \cfrac{2}{25}=\cfrac{m}{160}$

solve for "m"

5)

$\bf \textit{sprinkle park to parking lot}\quad \cfrac{drawing}{park}\qquad \cfrac{15}{60}\implies \cfrac{1}{4}
\\\\\\
\textit{playground to sprinkle park}\qquad \cfrac{drawing}{park}\qquad \cfrac{1}{4}=\cfrac{12}{p}$

solve for "p"

6)

$\bf \begin{array}{ccllll}
cake&people\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1&18\\
x&108
\end{array}\implies \cfrac{1}{x}=\cfrac{18 }{108}$

solve for "x".

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In May, Jim's lunch account has a balance of $58.19. If lunch costs 2.74 per day, how many days will Jim be able to buy lunch be

velikii [3]

He will be able to buy lunch for 21 days because 58.19 divided by 2.74 is 21. 237226

5 0

3 years ago

(a) Use a linear approximation to estimate f(0.9) and f(1.1). f(0.9) ≈ f(1.1) ≈ (b) Are your estimates in part (a) too large or

olasank [31]

Answer:

(Missing part of the question is attached)

$L(x)=2x+3$

Estimates are too large.

Step-by-step explanation:

Suppose the only information we know about the function is:

$f(1)=5$

where the graph of its derivative is shown in the attachment

If the function $f\\$ is differentiable at point $x=1$ , the tangent line to the graph of $f$ at 1 is given by the equation:

$y=f(1) +f'(1)(x-1)$

So we call the linear function:

$L(x)=f(1) +f'(1)(x-1)$

We know the $f(1)=5$ as it is given in the question, and $f'(1)=2$ from the graph attached. Substitute in the equation of $L(x)$ .

$L(x)=5+2(x-1)\\L(x)=5+2x-2\\L(x)=2x+3\\$

At x=1, $f'(x)$ is positive but it is decreasing. However. if we draw the tangent lines, we see that the tangent lines are becoming less steeper, so the tangent lines lie above the curve $f$ . Thus, The estimates are too large.

4 0

2 years ago

Math is hard help !!!!!

3241004551 [841]

Answer:

3000

Step-by-step explanation:

x = original amount of GHC

$\frac{1}{3} (\frac{1}{2}x)$ --> 1/6x = 500

x= 3000

7 0

3 years ago

F(x) = 2(x+3)2 -7<br><br><br> a= <br><br> h=<br><br> k=

vlabodo [156]

Answer:

Step-by-step explanation:

In vertex form, the equation is

y = a(x-h)^2 + k

So just read off the values!

6 0

3 years ago

A triangular course for a canoe race is marked with buoys. The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg

balu736 [363]

<h2>The race is 1.2 miles long</h2>

Step-by-step explanation:

The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg is 2/5 mi.

$\texttt{Length of first leg = }\frac{3}{10}miles\\\\\texttt{Length of second leg = }\frac{1}{2}miles\\\\\texttt{Length of third leg = }\frac{2}{5}miles$

Now we need to find length of race

$\texttt{Total length = }\frac{3}{10}+\frac{1}{2}+\frac{2}{5}\\\\\texttt{Total length = }\frac{3}{10}+\frac{5}{10}+\frac{4}{10}\\\\\texttt{Total length = }\frac{3+5+4}{10}\\\\\texttt{Total length = }\frac{12}{10}\\\\\texttt{Total length = }1.2miles$

The race is 1.2 miles long

7 0

3 years ago