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3 years ago

What is the perimeter of this tile 4in. 1in.? is it 10 in. or 10 in2power

Mathematics

1 answer:

coldgirl [10]3 years ago

3 0

P = 2 × 4in + 2 × 1in = 8in + 2in = 10in

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Find the value of x so that line m is parallel to line l.

MatroZZZ [7]

<h3>Answer: A) 46</h3>

Explanation:

The angles shown are same side interior angles.

For line L to be parallel to line M, the same side interior angles must be supplementary, or they must add to 180.

28+(3x+14) = 180

28+3x+14 = 180

3x+42 = 180

3x = 180-42

3x = 138

x = 138/3

x = 46

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Mademuasel [1]

Answer:

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Step-by-step explanation:

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2 years ago

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3 years ago

. Leslie is blowing up one of her favorite photographs to hang on her wall. If the photo's original length and height were 8 inc

Katena32 [7]

Answer:

$L_2 = 2\frac{2}{15}\ ft$

Step-by-step explanation:

Given

Original

$Length(L_1) = 8\ in$

$Height (H_1) = 15\ in$

New

$Height (H_2) = 4\ ft$

Required

Determine the new length (L2)

Since the original photographs was blown up; the original and the new photographs would have the same ratio

i.e.

$Ratio = L_1 : H_1$

and

$Ratio = L_2 : H_2$

Equate both ratios

$L_1 : H_1 = L_2 : H_2$

Rewrite as fraction

$\frac{L_1}{H_1} = \frac{L_2}{H_2}$

Substitute values for L1, H1 and H2

$\frac{8}{15} = \frac{L_2}{4}$

Multiply both sides by 4

$4 * \frac{8}{15} = \frac{L_2}{4} * 4$

$4 * \frac{8}{15} = L_2$

$\frac{4 * 8}{15} = L_2$

$\frac{32}{15} = L_2$

$2\frac{2}{15} = L_2$

$L_2 = 2\frac{2}{15}\ ft$

The new length must be $2\frac{2}{15}\ ft$

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3 years ago