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Katena32 [7]
3 years ago
12

−x+4y when x=−45 and y=13

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
7 0
-45+5(13)

65

-45+65=20
ExtremeBDS [4]3 years ago
5 0
If i am not mistaken, it would become 45+4(13). the -45 wouldn’t be negative because the -x is negative so negative + negative = positive. The answer should be 97.
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Which table represents the same linear relationship as y = 3x - 2?
Trava [24]

Answer:

Table 4  represents the same linear expression  as y = 3 x - 2.

Step-by-step explanation:

Here, the given expression is y = 3 x -2

So now check the any random pair of each table by putting in the given equation.

<u>TABLE 1 :  (2,-5)</u>

y = 3x -2  ⇒  -5 = 3(2) -2

or, -5 = -4 , NOT POSSIBLE

<u>TABLE 2 :  (0,3)</u>

y = 3x -2  ⇒  3 = 3(0) -2

or, 3 = -2 , NOT POSSIBLE

<u>TABLE 3 :  (1,2)</u>

y = 3x -2  ⇒  2 = 3(1) -2

or, 2 = 1 , NOT POSSIBLE

<u>TABLE 4 :  (1,1)</u>

y = 3x -2  ⇒  1 = 3(1) -2

or, 1 = 1 ,  POSSIBLE

checking for (2,4)

4 = 3(2) - 2  ⇒4 = 4 POSSIBLE

Here, table 4 satisfies the given points in the expression y = 3x -2

Hence, it represents the same linear expression .

3 0
2 years ago
A square pyramid has a base with an area of 20 square meters, and its lateral faces have a slant height of x meters. Sydney is c
svetoff [14.1K]
1. Consider the pyramid ABCDE in the figure 1 attached:

Each side of the square base equals \sqrt{20} = \sqrt{4*5} = \sqrt{4}* \sqrt{5}=2 \sqrt{5} (units)

Area of 1 lateral side of pyramid ABCDE is \frac{1}{2}* 2 \sqrt{5}*x=\sqrt{5}x

so the total lateral area is 4\sqrt{5}x (units squared)

and the total surface area is 20+4\sqrt{5}x (units squared)

2. Now consider the second figure KLMNP, Sydney's pyramid:

The lateral area is 4* \frac{1}{2}* 4 \sqrt{5} *2x=16 \sqrt{5}x

so the total area of the second pyramid is 20+16 \sqrt{5}x

So 2 things can be said about the areas:

i) the lateral area of Sydney's pyramid is \frac{16 \sqrt{5}x}{4\sqrt{5}x} =4 times larger than the lateral area of the original pyramid.

ii) The total area of Sydney's pyramid is (20+16 \sqrt{5}x)-(20+4\sqrt{5}x)=12\sqrt{5}x units squared larger than the total area of the original pyramid.

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3 years ago
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2 years ago
The length of a rectangle is one unit shorter than one-sixth of the width, x. Which expression represents the perimeter of the r
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Width: x
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