The height of broken part of tree from ground is 5.569m.
Justification:
Let BD is a tree of height 12 m.
<u>Suppose it got bent at a point C and let the part CD take the position CA, meeting the ground at A</u>.
i.e., CD = AC = h m
<u>Broken part makes 60° angle from ground</u>
So, ∠BAC = 60°
<u>Now, height of remaining part of tree</u> = (12 – h)m.
In right angled ∆ABC,
sin 60° = BC/AC
⇒ √3/2 = (12 - h)/h
⇒ √3h = 2(12 – h)
⇒ √3h = 24 – 2h
⇒ √3h + 2h = 24
⇒ h(√3 + 2) = 24
⇒ h(1.732 + 2) = 24
⇒ h(3.732) = 24
⇒ h = 24/3.732 = 6.4308 m
<u>Hence, height of broken tree from ground</u>
⇒ BC = 12 – h
⇒ 12 – 6.4308 = 5.569m
<u>Hence, tree is broken 5.569 m from ground</u>.
<u>Note</u>: See attached picture.
- Find the surface area when r is 8 inches and h is 8 inches.
A. 160π in²
B. 154π in²
C. 288π in²
D. 256π in² ☑
We are given –
⇢Radius of cylinder , r = 8 inches
⇢ Height of cylinder, h = 8 inches.
We are asked to find surface area of the given cylinder.
Formula to find the surface cylinder given by –

Now, Substitute given values –






- Henceforth,Option D is the correct answer.
It’s 42 heheeeee I’m Michel Jackson
1. =4/16 which in simplified terms = 1/4
2. = 37/99 (find the lowest common denominator which is 99 then multiply them, then combine fractions then subtract them)
3. 2/25
4. 12/18 which simplified is 2/3
5. 5/15 which simplified = 1/3
Hope you understand that:)
The general formula for the margin of error would be:
z * √[p (1-p) ÷ n]
where:
z = values for selected confidence level
p = sample proportion
n = sample size
Since the confidence level is not given, we can only solve for the
<span>√[p (1-p) ÷ n] part.
</span>
p = 44/70
n = 70
√[44/70 (1 - (44/70) ÷ 70]
√[0.6286 (0.3714)] ÷ 70
√0.2335 ÷ 70
√0.0033357 = 0.05775 or 0.058 Choice B.