Find the intercepts of the equations graph. 3x-4y= -12

Graph the function. g(x)=2(x +2)(x +6)g(x)=2(x+2)(x+6)

harkovskaia [24]

Answer:

Graph the parabola using its properties and the selected points. Direction: Opens Up Vertex: ( 4 , − 4 ) Focus: ( 4 , − 15 4 ) Axis of Symmetry: x = 4 Directrix: y = − 17 4 x y 2 0 3 − 3 4 − 4 5 − 3 6 0 image of graph

Hoped I helped

8 0

3 years ago

What is the median of the following data set -1000, -999, 1998, ..., -1, 0, 1, ..., 998, 999, 1000

qwelly [4]

Answer:

The correct answer option is C. 0.

Step-by-step explanation:

We are given the following data set and we are to find its median value:

$- 1 0 0 0 , - 9 9 9 , 1 9 9 8 , ... , -1 , 0 , 1 , ... , 9 9 8 , 9 9 9 , 1 0 0 0$

Median is the middle value of a data set which divides it into to halves.

The data set we have starts from -1000 and goes till 1000 which means there are total 2001 elements in it.

Therefore, 0 will the middle value which is the median for this data set.

7 0

3 years ago

Read 2 more answers

Y = 5/x/+2 Does it compress up 2 or stretch up 2

Dmitriy789 [7]

Answer:

It compresses up 2

Step-by-step explanation:

6 0

3 years ago

You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o

Aleksandr [31]

Answer:

Therefore the circumference of the circle is $=\frac{20\pi}{4+\pi}$

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

$\Rightarrow s=\frac{10-\pi r}{2}$

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

$A=\pi r^2+ (\frac{10-\pi r}{2})^2$

$\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2$

$\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}$

$\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25$

For maximum or minimum $\frac{dA}{dr}=0$

Differentiating with respect to r

$\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi$

Again differentiating with respect to r

$\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}$ > 0

For maximum or minimum

$\frac{dA}{dr}=0$

$\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0$

$\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}$

$\Rightarrow r=\frac{10}{4+\pi}$

$\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0$

Therefore at $r=\frac{10}{4+\pi}$ , A is minimum.

Therefore the circumference of the circle is

$=2 \pi \frac{10}{4+\pi}$

$=\frac{20\pi}{4+\pi}$

4 0

3 years ago

Sydney’s teacher says she may have her report card percentage based on either the mean or the median and she can drop one test s

svet-max [94.6K]

Answer:

Sydney should choose the median after dropping one test score.

Step-by-step explanation:

7 0

3 years ago