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pantera1 [17]
3 years ago
7

When a plot is sold for Rs. 18,700, the owner loses 15%. At what price must that plot be sold in order to gain 15%?

Mathematics
1 answer:
QveST [7]3 years ago
4 0

Answer: Rs. 25,300

Step-by-step explanation:

First find the original price of the plot:

Assume this price is x:

x * ( 1 - 15%) = 18,700

0.85x = 18,700

x = 18,700/0.85

x = Rs. 22,000

To make a gain of 15%, sell at:

= 22,000 * (1 + 15%)

= 22,000 * 1.15

= Rs. 25,300

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Leah borrows £10,000 over 5 years at a simple interest rate of 15%.
Fynjy0 [20]

Answer:

She will pay $7,500 interest over the 5 years

She will have to pay back $17,500 in total

Step-by-step explanation:

Let us revise the rule of the simple interest

<em>I</em> = <em>Prt</em> and <em>A</em> = <em>P</em>(1 +<em> rt</em>) , where:

  • A = Total Accrued Amount (principal + interest)
  • P = Principal Amount
  • I = Interest Amount
  • r = Rate of Interest per year in decimal
  • t = Time Period involved in months or years

∵ Leah borrows £10,000 over 5 years at a simple interest rate of 15%.

∴ P = 10,000

∴ t = 5

∴ r = 15% = \frac{15}{100} = 0.15

→ Substitute them in the first rule to find the interest

∵ I = 10,000(0.15)(5)

∴ I = 7,500

∴ She will pay $7,500 interest over the 5 years

→ Let us find A

∵ A = 10,000(1 + 0.15×5)

∴ A = 17,500

∴ She will have to pay back $17,500 in total

5 0
3 years ago
You have a babysitting job that pays $6 an hour. You also have
Natalka [10]

Answer:

One possibility is to work for (10) hours as a babysitter, and (10) hours as a cashier.

Step-by-step explanation:

An easy way to solve this problem is to set up a system to model the situation. Create one equation to model the money make, and the other to model the time spent. Let parameters (x) and (y) represent the time one spends at each job.

Since one cannot spend more than (20) hours a week working, set the first equation, for time, equal to (20),

x + y = 20

Now multiply each unit for the time by the money earned at each job, set this new equation equal to (150), the minimum amount of money one wishes to earn,

6(x) + 9(y) = 150

Thus the system is the following,

\left \{ {{x+y=20} \atop {6x+9y=150}} \right.

Now use the process of elimination. The process of elimination is when one multiplies one of the equations by a term such that when one adds the two equations, one of the variables cancels. One can solve for the other variable, and then backsolve for the first variable. Multiply the first equation by (-6) so that the variable (x) cancels.

\left \{ {{-6x-6y=-120} \atop {6x+9y=150}} \right.

Add the two equations,

3y=30

Use inverse operations to solve for (y),

y=10

Now substitute the value of (y) back into one of the original equations and solve for (x),

x+y=20

x+10=20

x=10

6 0
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Stuart bought a sweater on sale for 30% off the original price and another 25% off the discounted price. If the original price o
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Answer:

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Step-by-step explanation:

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