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Mekhanik [1.2K]

3 years ago

5

10 Points!

1 answer:

Gekata [30.6K]3 years ago

7 0

In this sequence, a₁ equals -1.

The difference between each term is +3, so the coefficient for n will be 3.

In the sequence, a₂ equals 2. The following equation will fit this sequence, and will be your answer:

$a_n = -1 + 3(n - 1)$

Proof:
$a_1 = -1 + 3(1 - 1) = -1 + 3(0) = -1$

$a_2 = -1 + 3(2 - 1) = -1 + 3(1) = -1 + 3 = 2$

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Need help with this!!

Taya2010 [7]

Answer:

The answer is B..... The corresponding is the identical number between all

The is 7 in each...

8 0

3 years ago

Identify the minimum value of the function y = 2x2 + 4x<br> Answer

iren2701 [21]

Answer:

(-1, -2)

Step-by-step explanation:

Find the <em>x</em>-value the minimum occurs at. Use this value to find the minimum value. (Graph to find the highest point)

4 0

3 years ago

Read 2 more answers

I will give branlist help asap

Elan Coil [88]

1. d = -9

2. m = -15

Hope this helped! (:

5 0

2 years ago

For the polynomial function ƒ(x) = x4 −25x2, find the zeros. Then determine the multiplicity at each zero and state whether the

AfilCa [17]

<u>ANSWER</u>

The zeros are $x=-5,x=0,x=5$

EXPLANATION

Given;

$f(x)=x^4-25x^2$ .

We can rewrite the function as

$f(x)=x^2(x^2-25)$

$\Rightarrow f(x)=x^2(x^2-5^2)$

$\Rightarrow f(x)=x^2(x-5)(x+5)$

The zeros are found by equating the function to zero.

$\Rightarrow x^2(x-5)(x+5)=0$

$\Rightarrow (x-5)=0$

The multiplicity is 1, since it is odd the graph crosses at this intercept. which is $x=5$

Or

$\Rightarrow (x+5)=0$

The multiplicity is 1, since it is odd the graph crosses at this intercept. which is $x=-5$

Or

$\Rightarrow x^2=0$

This last root has a multiplicity of 2.

That is

$x=0$ repeats two times.

Since the multiplicity is even, the graph touches the x-axis at the point $x=0$ .

See graph.

5 0

3 years ago

12x−39≤9 AND−4x+3<−6, just solving for x<br><br> please answer ASAP

kari74 [83]

<u>Answer:</u>

Solving for x in 12x − 39 ≤ 9 and −4x + 3 < −6 we get 2.25 < x ≤ 4

<u>Solution</u>:

Need to find the value of x which satisfies following two given expressions

12x − 39 ≤ 9 ------(1)

−4x + 3 < −6 ------ (2)

Lets first solve expression (1)

12x − 39 ≤ 9

Adding 39 on both sides , we get

12x−39 + 39 ≤ 9 +39

=>12x ≤ 48

=> x ≤ 48/12

=> x ≤ 4

Now solving expression (2)

−4x+3<−6

=> -4x < -6 – 3

=> -4x < -9

=> 4x > 9

=> x > 9/4

=> x > 2.25

So from solution of expression (1) and (2) , we get x ≤ 4 and x > 2.25

Hence required value of x is 2.25 < x ≤ 4.

7 0

3 years ago