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mixas84 [53]
3 years ago
8

What are the values of m and e in the diagram below?​

Mathematics
1 answer:
elena55 [62]3 years ago
4 0
Please add the picture.
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If you have a cubic polynomial of the form y = ax^3 + bx^2 + cx + d and lets say it passes through the points (2,28), (-1, -5),
nikklg [1K]

Step-by-step explanation:

<u>Step 1:  Solve using the first point</u>

<em>(2, 28)</em>

28 = a(2)^3 + b(2)^2 + c(2) + d

28 = 8a + 4b + 2c + d

<u>Step 2:  Solve using the second point</u>

<em>(-1, -5)</em>

-5 = a(-1)^3 + b(-1)^2 + c(-1) + d

-5 = -a + b - c + d

<u>Step 3:  Solve using the third point</u>

<em>(4, 220)</em>

220 = a(4)^3 + b(4)^2 + c(4) + d

220 = 64a + 16b + 4c + d

<u>Step 4:  Solve using the fourth point</u>

<em>(-2, -20)</em>

-20 = a(-2)^3 + b(-2)^2 + c(-2) + d

-20 = -8a + 4b - 2c + d

<u>Step 5:  Combine the first and fourth equations</u>

<u />28 - 20 = 8a - 8a + 4b + 4b + 2c - 2c + d + d

8 = 8b + 2d

8 - 8b = 8b - 8b + 2d

(8 -8b)/2 = 2d/2

4 - 4b = d

<u>Step 6:  Solve for c in the second equation</u>

-5 + 5 = -a + b - c + d + 5

0 + c = -a + b - c + c + d + 5

c = -a + b + d + 5

<u>Step 7:  Substitute d with the stuff we got in step 5</u>

c = -a + b + (4 - 4b) + 5

c = -a + b + 4 - 4b + 5

c = -a - 3b + 9

<u>Step 8:  Substitute d and c into the first equation</u>

<u />28 = 8a + 4b + 2(-a - 3b + 9) + (4 - 4b)

28 = 8a + 4b - 2a - 6b + 18 + 4 - 4b

28 - 22 = 6a - 6b + 22 - 22

6 / 6 = (6a - 6b) / 6

1 + b = a - b + b

1 + b = a

<u>Step 9:  Substitute a, b, and c into the third equation</u>

220 = 64(1 + b) + 16b + 4(-(1 + b) - 3b + 9) + (4 - 4b)

220 = 64 + 64b + 16b + 4(-1 - b - 3b + 9) + 4 - 4b

220 - 100 = 60b + 100 - 100

120 / 60 = 60b / 60

2 = b

<u>Step 10:  Find a using b = 2</u>

a = b + 1

a = (2) + 1

a = 3

<u>Step 11:  Find c using a = 3 and b = 2</u>

c = -a - 3b + 9

c = -(3) - 3(2) + 9

c = -3 - 6 + 9

c = 0

<u>Step 12:  Find d using b = 2</u>

d = 4 - 4b

d = 4 - 4(2)

d = 4 - 8

d = -4

Answer:  a = 3, b = 2, c = 0,d = -4

6 0
3 years ago
Read 2 more answers
Please help got to get grade up
dusya [7]

Answer:

10

Step-by-step explanation:

The ratio of abc/def=1.5

15/1.5=10

if you have insta follow me if you want at riztofu

5 0
2 years ago
Jaime drew the number line below to show 2/3 4/5. Explain how the number line shows 2/3 times 4/5. What is the product?
bearhunter [10]

Answer:

\frac{2}{3} * \frac{4}{5} = \frac{6}{15}

Step-by-step explanation:

Given

\frac{2}{3} * \frac{4}{5} =

The number line is missing from the question.

So, I will answer the question and also draw the number line to show the product.

\frac{2}{3} * \frac{4}{5} =

\frac{2}{3} * \frac{4}{5} = \frac{6}{15}

To represent this on a number line;

We draw a number line of 15 points, and place a dot on the 6th point.

This represents 6/15

See attachment

8 0
3 years ago
Are the functions f(x) = (x^2-1)/(x-1) and g(x)= x+1 equal for all x?
Vinvika [58]
\bf \textit{difference of squares}&#10;\\ \quad \\&#10;(a-b)(a+b) = a^2-b^2\qquad \qquad &#10;a^2-b^2 = (a-b)(a+b)\\\\&#10;-------------------------------\\\\

\bf f(x)=\cfrac{x^2-1}{x-1}\implies f(x)=\cfrac{x^2-1^2}{x-1}\implies f(x)=\cfrac{(\underline{x-1})(x+1)}{\underline{x-1}}&#10;\\\\\\&#10;f(x)=x+1\qquad \qquad \qquad  \qquad  \qquad  g(x)=x+1\\\\&#10;-------------------------------\\\\&#10;\textit{they're, kinda, except that, when x = 1}&#10;\\\\\\&#10;g(x)=(1)+1\implies g(x)=2&#10;\\\\\\&#10;f(x)=\cfrac{(1)^2-1}{(1)-1}\implies f(x)=\cfrac{0}{0}\impliedby und efined
7 0
3 years ago
DISCRETE MATHEMATIC
Jet001 [13]

Answer:

The conclusion "T" logically follows from the premises given and the argument is valid

Step-by-step explanation:

Let us use notations to represent the steps

P: I take a bus

Q: I take the subway

R: I will be late for my appointment

S: I take a taxi

T: I will be broke

The given statement in symbolic form can be written as,

(P V Q) → R

S → (¬R ∧ T)

(¬Q ∧ ¬P) → S

¬R

___________________

∴ T

PROOF:

1. (¬Q ∧ ¬P) → S                Premise

2. S → (¬R ∧ T)                  Premise

3. (¬Q ∧ ¬P) → (¬R ∧ T)    (1), (2), Chain Rule

4. ¬(P ∨ Q) → (¬R ∧ T)      (3), DeMorgan's law

5. (P ∨ Q) → R                   Premise

6. ¬R                                 Premise

7. ¬(P ∨ Q)                        (5), (6), Modus Tollen's rule

8. ¬R ∧ T                          (4), (7), Modus Ponen's rule

9. T                                   (8), Rule of Conjunction

Therefore the conclusion "T" logically follows from the given premises and the argument is valid.

6 0
3 years ago
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