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3 years ago

A car Travel 476 miles on 14 gallons of gas. Write an eqation relating the distance d to the nuber of gallons

1 answer:

Klio2033 [76]3 years ago

3 0

476miles per 14gallons of gas

is the same as 476 / 14 = 34

so 34miles / 1gallon of gas.

34x =578 where x is the number of gallons

578 / 34 = 17gallons

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The Anderson family is preparing for a family reunion. They think they will need 22 juice boxes for every 6 children who attend.

BlackZzzverrR [31]

Answer:

Step-by-step explanation:

22 for every six kids

12 is 6 doubled so you double 22 to get 44

8 0

2 years ago

Read 2 more answers

3x-8y=24 <br> y=x-8<br> Please show <br> work

In-s [12.5K]

Answer:

3x - 8y = 24 --------(1)

y = x - 8 ---------(2)

substitute y in (1)

3x - 8( x - 8) = 24

3x - 8x + 64 = 24

-5x = 24 - 64

-5x = -40

5x = 40

x= 8

substitute x in (2)

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2 years ago

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Ray has found that his new car gets 31 miles per gallon on the highwayand 26 miles per gallon in the city. He recently drove 285

Mkey [24]

Answer:

$Highway = 155\ miles$

$City = 130\ miles$

Step-by-step explanation:

Given

$Highway = 31mi/gallon$

$City = 26mi/gallon$

$Total\ Miles = 285$

$Total\ Gallons = 10$

Required

Determine the number of miles driven on the highway and on the city

Represent the gallons used on highway with h and on city with c.

So, we have:

$c + h = 10$ ---- gallons used

and

$31h + 26c = 285$ --- distance travelled

In the first equation, make c the subject

$c = 10 - h$

Substitute 10 - h for c in the second equation

$31h + 26c = 285$

$31h + 26(10 - h) = 285$

Open bracket

$31h + 260 - 26h = 285$

Collect like terms

$31h - 26h = 285 - 260$

$5h = 25$

Make h the subject

$h = \frac{25}{5}$

$h = 5$

Substitute 5 for h in $c = 10 - h$

$c = 10 - 5$

$c = 5$

If on the highway, he travels 31 miles per gallon, then his distance on the highway is:

$Highway = 31 * 5$

$Highway = 155\ miles$

If in the highway, he travels 26 miles per gallon, then his distance on the highway is:

$City = 26 * 5$

$City = 130\ miles$

8 0

2 years ago

Determine the point on the graph of the linear equation 2x + 5y = 19, whose ordinate is 1 1/2 times its abscissa.

rosijanka [135]

Answer:

(2, 3)

Step-by-step explanation:

2x + 5y = 19

5y = -2x + 19

y = $-\frac{2}{5} x + \frac{19}{5}$

P(abscissa, ordinate)

P(x, 1.5x)

P(2, 3)

$3 = -\frac{2}{5} (2) + \frac{19}{5}$

$3 = -\frac{4}{5} + \frac{19}{5}$

3 = 15/5

3 = 3

8 0

3 years ago

Write as a decimal. If a repeating decimal, round to the nearest hundredth.

Mamont248 [21]

Given:

$\frac{475}{80}$

Let's evaluate and find the quotient.

We have:

$\frac{475}{80}=5.9375$

SInce it is not a repeating decimal, we are asked to leave to answer as it is.

A repeating decimal is a decimal with digits or group of digits that repeats endlessly.

The decimal 5.937

ANSWER:

5.9375

6 0

1 year ago