Answer : Interval to Inequality
(a, +∞) x > a "greater than a"
[a, +∞) x ≥ a "greater than or equal to a"
(-∞, a) x < a "less than a"
(-∞, a] x ≤ a "less than or equal to a"
I hope you find this helpful
You could apply a clever Algebra trick to avoid using the quotient rule,


and apply power rule into chain rule from that point.
But this problem was likely designed to teach you about quotient rule so let's do it that way.
Let's start by "setting up" our quotient rule:

If this log notation is not intended to be natural log, then we'll have a little bit of extra work. Our change of base identity allows us to rewrite log base 10 in terms of the natural log,

so let's apply this to our problem,

Derivative of ln(x) gives us 1/x in each case,

Factor the 1/(x ln10) out of each term in the numerator,

and combine like-terms,

Lemme know if you're confused with any of the steps.
Step-by-step explanation:
it is the vertex form.
remember, (h, k) is the vertex point.
the vertex being the point of the (quadratic) parabola, where the curve turns around.
depending on the orientation of the parabola (vertex up or vertex down) as defined by the sign of a, this is either the minimum or the maximum of the curve.
so, the first a. is correct.
and so is the second a., as they play an important role when completing the square and hence finishing the transformation.
Pretty sure Desmos will help you with this more than anything else, but here goes:
The maximum height reached is 66.016. The ball will hit the ground in 4 seconds. The best domain is -0.063≤x≤4. I'm not too sure about -0.063, it's either -0.063 or -1.
Hope this helps!
Answer:
ok
Step-by-step explanation:
ok