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2 years ago

14

John is saving money to buy a game. so far he has saved $12 , which is one-fourth of the total cost of the game. how much does t

he game cost?

1 answer:

Dovator [93]2 years ago

4 0

One fourth of the game cost $3

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Plllzzz im new and i neeed help

ella [17]

Answer:

4082

Step-by-step explanation:

Given

The composite object

Required

The volume

The object is a mix of a cone and a hemisphere

Such that:

<u>Cone</u>

$r = 10cm$ ---- radius (r = 20/2)

$h = 19cm$

<u>Hemisphere</u>

$r=10cm$

The volume of the cone is:

$V_1 = \frac{1}{3}\pi r^2h$

$V_1 = \frac{1}{3}\pi * 10^2 * 19$

$V_1 = \frac{1900}{3}\pi$

The volume of the hemisphere is:

$V_2 = \frac{2}{3}\pi r^3$

$V_2 = \frac{2}{3}\pi 10^3$

$V_2 = \frac{2000}{3}\pi$

So, the volume of the object is:

$V = V_1 + V_2$

$V = \frac{1900}{3}\pi + \frac{2000}{3}\pi$

$V = \frac{3900}{3}\pi$

$V = 1300\pi$

$V = 1300 * 3.14$

$V = 4082$

8 0

3 years ago

Bro ? What is this ? Rocket science ? HELP ME PLSSS.

Liono4ka [1.6K]

Answer:

Step-by-step explanation:

4 0

1 year ago

The U.S.-based motorcycle manufacturer says that it expects to build $150,000 motorcycles this year, up from $133,000 last year.

Leokris [45]

Answer:

Step-by-step explanation:

(148-134)/134 = x%

14/134 = x%

x = 10.4%

Have a great day

:)

4 0

2 years ago

Read 2 more answers

A college football coach has decided to recruit only the heaviest 15% of high school football players. He knows that high school

Alla [95]

Answer:

The coach should start recruiting players with weight 269.55 pounds or more.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 225 pounds

Standard Deviation, σ = 43 pounds

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.15

$P( X > x) = P( z > \displaystyle\frac{x - 225}{43})=0.15$

$= 1 -P( z \leq \displaystyle\frac{x - 225}{43})=0.15$

$=P( z \leq \displaystyle\frac{x - 225}{43})=0.85$

Calculation the value from standard normal z table, we have,

$P(z < 1.036) = 0.85$

$\displaystyle\frac{x - 225}{43} = 1.036\\\\x = 269.548 \approx 269.55$

Thus, the coach should start recruiting players with weight 269.55 pounds or more.

3 0

3 years ago

I will give branlist help asap

Elan Coil [88]

1. d = -9

2. m = -15

Hope this helped! (:

5 0

2 years ago