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Vaselesa [24]
3 years ago
9

A random sample of size 21 was taken from a normal population. the sample average was 9.87 and the sample sd was 1.17. at the si

gnificance level of 10%, what test should you use for testing whether the population mean equals 9.7?
Mathematics
1 answer:
Olin [163]3 years ago
6 0
You should be using a hypothesis test - One sample T test.   

The answer is given below.  

Test of mu = 9.7 vs not = 9.7  

The assumed standard deviation = 1.17    

N Mean SE Mean 90% CI Z P  

21 9.87000 0.25531 (9.45004, 10.28996) 0.67 0.506  

since P value is greater than 0.05 we accept the null hypothesis that the population mean equals 9.7
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Step-by-step explanation:

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Onyango is now three times as old as his daughter and four times as old as his son. Eight years from now, Onyango’s age will be
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Brainliest please

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Step-by-step explanation:

<h3>use algebra</h3>

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8+3a+a+8+3/4a+a

a+8+3/4a+a

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4 years ago
3.274 x 10^3 as an ordinary number
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327.4

Step-by-step explanation:

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4 0
4 years ago
Read 2 more answers
Can someone please help
MissTica

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I'm Sure You Got The Answer Your Smart

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Answer:

D. 96

F. 32

Step-by-step explanation:

The inequality 3x ≥ 96, means that x and 3 must be multiplied to get a product that is <u><em>greater</em></u> than 96.  So to figure this out, you must plug in the numbers given for x, like so:

3x ≥ 96

A. 3(31) ≥ 96

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A tip that makes this easier is that, you can see that 31 multiplied by 3 is 93, which is only a couple numbers off 96, so all numbers after 31 will result in a product greater than 96. For example:

D. 3(96) ≥ 96

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The inequality sign states that the number must be either greater or equal to 96, which it is.

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3 years ago
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