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2 years ago

How to write a standard form equation with an undefined slope?

1 answer:

8 0

An equation that has an undefined slope is a vertical line. A vertical line is represented by x = a number. You cannot write an equation for a vertical line in slope intercept form (because of the undefined slope)...but u can write it in standard form.

lets say u have a vertical line going thru (2,3).....since it is a vertical line, its equation would be x = 2

to write this in standard form, it would be : x + 0y = 2 <==

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Find the derivative of 3e^y+x=y

Sindrei [870]

You have the following function:

$y=3e^y+x$

Derivate implictly the previous expression, as follow:

$y^{\prime}=3e^yy^{\prime}+1$

Where you have used that:

$(e^y)^{\prime}=e^yy^{\prime}$

Then, the implicit derivative of the given expression is:

$y^{\prime}=3e^yy^{\prime}+1$

Next, solve for y' as follow:

$\begin{gathered} y^{\prime}-3e^yy^{\prime}=1 \\ (1-3e^y)y^{\prime}=1 \\ y^{\prime}=\frac{1}{1-3e^y} \end{gathered}$

4 0

1 year ago

Find the factors of x^3 + z^3

bixtya [17]

So to factor
factor out a x+z
(x+z)(x^2-xz+z^2)
the factors are
x+z and x^2-xz+z^2

5 0

3 years ago

72 ounces in 6 steaks

svet-max [94.6K]

12 ounces for each steak ..............

6 0

2 years ago

Read 2 more answers

A. A parabola opening upward, shifted 8 units right, and 5 units down.

Lesechka [4]

Answer:

A) y=(x-8)^2-5

B)y=10(x+6)^2

C) y=-0.6(x+7)^2-2

Step-by-step explanation:

5 0

3 years ago

Find the solutions of the quadratic equation -9c² +2 +3 = 0.

Tresset [83]

Given that,

An equation : -9c² +2c +3 = 0

To find,

Find the value of x.

Solution,

We have, -9c² +2c +3 = 0

We can solve it using the formula as follows :

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here, a = -9, b = 2 and c =3

Put the values,

$c=\dfrac{-2\pm \sqrt{(2)^2-4(-9)(3)}}{2(-9)}\\\\c=\dfrac{-2+\sqrt{(2)^{2}-4(-9)(3)}}{2(-9)}, \dfrac{-2-\sqrt{(2)^{2}-4(-9)(3)}}{2(-9)}\\\\c=-0.47, 0.69$

So, the solution are -0.47 and 0.69.

8 0

3 years ago