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harkovskaia [24]
4 years ago
6

What are two equivalent fractions for 5/6?

Mathematics
2 answers:
notsponge [240]4 years ago
6 0

Answer:

10/12 and 15/18

Step-by-step explanation:

You multiply both sides by 2 and then 3

Ainat [17]4 years ago
5 0
Two equivalent fractions are 20/24 and 25/30
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Factor the following expression completely. 16x^5-x^3<br> A. <br><br> B. <br><br> C. <br><br> D.
Ket [755]

Answer:

x^3(2x+1)(2x-1)

Step-by-step explanation:

first take common then use formula of a^2-b^2

6 0
3 years ago
Read 2 more answers
Help Link (little green guy on the left) defeat Ganon and save Zelda. Find the distance from Link to the Green Soldier so Link c
kenny6666 [7]

Answer:

5 Units.

Step-by-step explanation:

In the attached diagram, Link is at (0,1) and Ganon is at (4,4)

To find the distance between the two, we use the distance formulaDistance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

(x_1,y_1)=(0,1), (x_2,y_2)=(4,4)

Distance between Link and Ganon=\sqrt{(4-0)^2+(4-1)^2}

=\sqrt{4^2+3^2}\\=\sqrt{16+9}\\=\sqrt{25}

=5 Units

The distance between the two is 5 Units.

3 0
3 years ago
Find the sum. Include all calculations in your answer.
Andreas93 [3]

Answer:

- 2 2/7

Step-by-step explanation:

First, do the conversion:

[-(6*7)+3]/7 = -39/7

[(3*7)+2]/7 = 23/7

Then calculate the result:

23/7 - 39/7 = -16/7 or - 2 2/7

6 0
3 years ago
As Greg swam across an 80 - meter river, the current carried him 30 m downstream. How
Leya [2.2K]

Answer:

85.44

Step-by-step explanation: bee go buzz squared by 2

8 0
3 years ago
Find three consecutive even integers such that the sum of the least integer and the middle integer is 3030 more than the greates
Genrish500 [490]
X = <span> least integer
x + 2 = </span><span>middle integer
x + 4 = </span><span>greatest integer

x + x + 2 - (x + 4) = 3030
2x + 2 - x - 4 = 3030
x - 2 = 3030
x = 3030 + 2  
x = 3032  </span>← least integer

middle integer = x + 2 = 3034

greatest integer = x + 4 = 3032 + 4 = 3036

Check:
3032 + 3034 = 6066
3036 + 3030 = 6066
6066 = 6066

3 0
3 years ago
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