What mathematical process is the following formula performing: C2*D3?

Mathematics

2 answers:

tiny-mole [99]3 years ago

8 0

Answer is D because C^2 ×D^2 the * mean ×

bekas [8.4K]3 years ago

8 0

Answer:

D. Multiplication

Step-by-step explanation:

Multiplication is a term with origin in Latin multiplicatio that allows to name the fact and the consequences of multiplying or multiplying (increase the number of things that belong to the same group).

For mathematics, multiplication consists of a composition operation that repeatedly requires adding a number according to the number of times indicated by another.

The numbers involved in multiplication are called factors, while the result is called product. The objective of the operation, therefore, is to find the product of two factors.

Each factor, on the other hand, has its own denomination: the number to be added repeatedly is the multiplying, while the number that indicates the number of times to multiply is the multiplier. In short, multiplication consists in taking the multiplication and adding it as many times as units the multiplier contains.

In this case:

C^2 * D^3

where

* is the mathematical expression to multiply, also symbolized as x

C^2 and D^3 are the factors

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Find all points on the x-axis that are 14 units from the point (6,-7) All points on the x-axis that are 14 units from the point

Maksim231197 [3]

Answer: $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

or (18.124,0) and ( -6.124,0) are the required points.

Step-by-step explanation:

Let (x,0) be the point on x -axis that are 14 units from the point (6,-7) .

Then by distance formula , we have

$\sqrt{(x-6)^2+(0-(-7))^2}=14\ \ \ [\ \because distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]$

Taking square on both the sides , we get

$(x-6)^2+7^2=14^2\\\\\Rightarrow\ x^2+6^2-2(6)x+49=196\\\\\Rightarrow\ x^2+36-12x=147\\\\\Rightarrow\ x^2-12x=111\\\\\Rightarrow\ x^2-12x-111=0$

Using quadratic formula : $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{12\pm\sqrt{(-12)^2-4(1)(-111)}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{144+444}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{588}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{2^2\times7^2\times3}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm14\sqrt{3}}{2}\\\\\Rightarrow\ x=6\pm7\sqrt{3}$