Answer:
I think first add the side 137+ 127 +118=382 / 382cm
A. The function is bing translated down 5 units
b. The function is being stretched vertically stretched by 2 units
c. He function is being translated 5 units to the right
d. The functions being flipped and vertically stretched by 3 units
Answer: The correct option is triangle GDC
Step-by-step explanation: Please refer to the picture attached for further details.
The dimensions give for the cube are such that the top surface has vertices GBCF while the bottom surface has vertices HADE.
A right angle can be formed in quite a number of ways since the cube has right angles on all six surfaces. However the question states that the diagonal that forms the right angle runs "through the interior."
Therefore option 1 is not correct since the diagonal formed in triangle BDH passes through two surfaces. Triangle DCB is also formed with its diagonal passing only along one of the surfaces. Triangle GHE is also formed with its diagonal running through one of the surfaces.
However, triangle GDC is formed with its diagonal passing through the interior as shown by the "zigzag" line from point G to point D. And then you have another line running from vertex D to vertex C.
Given:
After driving for 20 minutes, Juan was 62 miles away from his apartment.
After driving for 32 minutes Juan was only 38 miles away.
The time driving and the distance away from his apartment form a linear relationship.
To find:
The independent and dependent variables.
Solution:
If the value of a variable depends on the another, then it is called dependent variables.
If the value of a variable does not depend on the another, then it is called independent variables.
In the given problem, the distance of Juan from his apartment depends on the time he drove. So,
Dependent variable = Distance of Juan from his apartment in miles.
Independent variable = Time he drove
Answer:
-5i and 5i cannot be roots of the equation, since they are complex.
Step-by-step explanation:
A 3-degree polynomial equation must have 3 roots, if one of its roots is a complex number, then its conjugate must also be a root of the function. The problem already stated two roots, which are reals, therefore the last root must also be real. Using this line of thought we know that -5i and 5i cannot be roots of the equation, since they're complex.