All categories

2 years ago

PLEASE HELP!! I COULDNT PAY ATTENTION IN CLASS TODAY

Mathematics

1 answer:

rosijanka [135]2 years ago

6 0

I’m pretty sure it’s 6x20=120 and then for the other missing box it’s 120

You might be interested in

Identify the transformations y = |x| ‐ 6

siniylev [52]

Thé transformation is that the function moved 6 units down

4 0

2 years ago

Suppose that the revenue function for a certain product is given by R(x) = 17(2x + 1)−1 + 34x − 17 where x is in thousands of un

REY [17]

Answer:

Step-by-step explanation:

Given that:

R(x) = $\frac{17}{2x+1}$ + 34x − 17

As we know that derivative of revenue function is marginal revenue function .

We will use following rules of derivative

=> dR/ dx = $\frac{-17*2}{(2x+1)^{2} } + 34$

=> R' (x) = $\frac{-34}{(2x+1)^{2} } + 34$

=> R '(2000) = $\frac{-34}{(2*2000+1)^{2} } + 34$ = 34

The revenue when 2000 units are sold is:

R(2000) = $\frac{17}{2*2000+1}$ + 34*2000 − 17 = $69,783

3 0

3 years ago

Is this a quadratic function 2x+13=13

lys-0071 [83]

Answer:

Step-by-step explanation:

Simplifying

2x + 13 = 0

Reorder the terms:

13 + 2x = 0

Solving

13 + 2x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-13' to each side of the equation.

13 + -13 + 2x = 0 + -13

Combine like terms: 13 + -13 = 0

0 + 2x = 0 + -13

2x = 0 + -13

Combine like terms: 0 + -13 = -13

2x = -13

Divide each side by '2'.

x = -6.5

Simplifying

x = -6.5

7 0

2 years ago

What is the expression in radical form?<br><br> (4x3y2)310

sertanlavr [38]

Given:

Consider the given expression is

$(4x^3y^2)^{\frac{3}{10}}$

To find:

The radical form of given expression.

Solution:

We have,

$(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

Therefore, the required radical form is $\sqrt[5]{8y^3}\sqrt[10]{x^9}$ .

8 0

3 years ago

Ignore that bottom but help pleaseee

NNADVOKAT [17]

The answer is 49 because it is

7 0

2 years ago