The longest side of an acute triangle measures 30 inches. The two remaining sides are congruent, but their length is unknown. Wh
at is the smallest possible perimeter of the triangle, rounded to the nearest hundredth?
2 answers:
Answer:
72.4 in.
Step-by-step explanation:
If the triangle were right-angled then the other 2 sides would be of length 30 / sqrt2 = 21.213 inches.
But it is acute angled so they will be a bit longer than this
they could be say 21.215 inches
So the required perimeter = 30 + 2*21.215 = 72.43 inches to nearest hundredth
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