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3 years ago

The ratio of boys to girls is 4:3 .T here are 35 students in a class how many students are boys ?? Pleaseee help

1 answer:

8 0

There are 20 boys in the class. The ratio is 4:3 so that means 4 out of 7 are boys and 3 out of 7 are girls. Divide 35 by 7 and you get 5. 5 times 4 is 20. 5 times 3 is 15. add them together and you have 35 students in total. So 20 students are boys and 15 students are girls.

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Twenty-four is ___% of 80

Ugo [173]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

3.) A glass of water is being filled up slowly. It initially starts out with 4

maria [59]

Answer:

8 minutes

Step-by-step explanation:

The amount in the glass after m minutes can be described by ...

a = 4 + 3/2m

We want to find m when a=16, so ...

16 = 4 + 3/2m

12 = 3/2m . . . . . subtract 4

8 = m . . . . . . . . . multiply by 2/3

It will take 8 minutes to fill the glass.

4 0

3 years ago

The binomial x-2 is a factor of the polynomial below. f(x)=x3+x2+nx+10 What is the value of n?

Nutka1998 [239]

<h3>Answer: n = -11</h3>

=========================================================

Explanation:

Since x-2 is a factor of f(x), this means f(2) = 0.

More generally, if x-k is a factor of p(x), then p(k) = 0. This is a special case of the remainder theorem.

So if we plugged x = 2 into f(x), we'd get

f(x) = x^3+x^2+nx+10

f(2) = 2^3+2^2+n(2)+10

f(2) = 8+4+2n+10

f(2) = 2n+22

Set this equal to 0 and solve for n

2n+22 = 0

2n = -22

n = -22/2

n = -11 is the answer

Therefore, x-2 is a factor of f(x) = x^3+x^2-11x+10

Plug x = 2 into that updated f(x) function to find....

f(x) = x^3+x^2-11x+10

f(2) = 2^3+2^2-11(2)+10

f(2) = 8+4-22+10

f(2) = 0

Which confirms our answer.

3 0

3 years ago

Add the followinf expresion<br>b. x- 3y + 4z , y – 2x- 8z ,5x – 2y – 3z

Mariana [72]

Answer:

4x - 4y - 7z

Step-by-step explanation:

x - 3y + 4z + y - 2x - 8z + 5x - 2y - 3z =

(x - 2x + 5x) + (y - 3y - 2y) + (4z - 8z - 3z) =

4x + (- 4y) + (-7z) =

4x - 4y - 7z <===

3 0

3 years ago

Given the equation 5x − 4 = –2(3x + 2), solve for the variable. Explain each step and justify your process.

blagie [28]

A.
$5x-4=-2(3x+2) \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
5x-4=-2 \times 3x-2 \times 2 \\
5x-4=-6x-4 \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 6x to both sides} \\
11x-4=-4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 4 to both sides} \\
11x=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{divide both sides by 11} \\
x=0$

B.
$3(2x-4)=5x-1 \\
6x-12=5x-1 \\
\boxed{11x-12=-1} \Leftarrow \hbox{the first mistake} \\
11x=11 \\
\boxed{x=11} \Leftarrow \hbox{the second mistake}$

Megan's solution isn't correct.
The first mistake: she subtracted 5x from the right-hand side of the equation, but added 5x to the left-hand side.
The second mistake: she divided the right-hand side of the equation by 11, but didn't divide the left-hand side.

The correct solution:
$3(2x-4)=5x-1 \ \ \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
3 \times 2x+3 \times (-4)=5x-1 \\ 6x-12=5x-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{subtract 5x from both sides} \\
x-12=-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 12 to both sides} \\
x=11$

3 0

3 years ago