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sp2606 [1]
3 years ago
6

Which of the following coordinates is located in Quadrant IV?

Mathematics
2 answers:
kupik [55]3 years ago
5 0
(4,-2) is located in Quadrant IV
kodGreya [7K]3 years ago
4 0
Answer: (4, -2) or A

Step by Step Explanation:
The photo on this message are the quadrants, to be in quadrant IV or 4; x needs to be positive and y needs to be negative, so (4,-2) will be in Quadrant IV

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3 years ago
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Read 2 more answers
Given the position of the particle, what the position(s) of the particle when it’s at rest
choli [55]

The position function of a particle is given by:

X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t

The velocity function is the derivative of the position:

\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}

The particle will be at rest when the velocity is 0, thus we solve the equation:

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The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Substituting:

\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}

We have two possible answers:

\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

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6 0
1 year ago
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1. Locate and label the following numbers on the number line:
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Step-by-step explanation:

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