Answer:
6042915 balls.
Step-by-step explanation:
Volume of a ping pong ball is;
V = (4/3)πr³
diameter of ping pong ball is given 4cm = 0.04 m
Radius; r = 0.04/2 = 0.02 m
V = (4/3)π(0.02³)
V = 0.00003351032 m³
Room is 9.5 meters long, 7.5 meters wide, and 3 meters high.
Volume; V = 9 × 7.5 × 3 = 202.5 m³
Number of ping pong balls that will fit into the room = volume of room/volume of ping pong balls = 202.5/0.00003351032 = 6042914.540956151
Approximately 6042915 balls.
Answer:
- ![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
Step-by-step explanation:
Given
![\frac{x^2y^8}{x^7y^6}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2y%5E8%7D%7Bx%5E7y%5E6%7D)
= ![\frac{y^{(8-6)} }{x^{(7-2)} }](https://tex.z-dn.net/?f=%5Cfrac%7By%5E%7B%288-6%29%7D%20%7D%7Bx%5E%7B%287-2%29%7D%20%7D)
=
, substitute values
= ![\frac{4^2}{(-2)^{5} }](https://tex.z-dn.net/?f=%5Cfrac%7B4%5E2%7D%7B%28-2%29%5E%7B5%7D%20%7D)
= ![\frac{16}{-32}](https://tex.z-dn.net/?f=%5Cfrac%7B16%7D%7B-32%7D)
= - ![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
Answer:
We set up our equations:
35x+40y = 1850 eq1
x+y = 50 eq2
Substituting eq 2 into eq 1,
35x+40(50-x) = 1850
35x+2000-40x = 1850
-5x+2000 = 1850
-5x = -150
x = 30
Substitute value of x into eq 2.
x+y = 50
30+y = 50
y = 20
Car 1 consumes 30 gallons of gas.
Car 2 consumes 20 gallons of gas.
hope this helps