Answer:
a. Inversion
b. Duplication
Explanation:
Inversion has the name suggest, has to do with a segment of DNA being reversed from end to end.
In this case here,
Inversion is taking place here.
species 1 ATGCAAATTTGGGCCCATGAATGGTTGCAA
species 2 ATGCAAAAATTTTGGTACGCCGAATGGTTGCAA
Therefore, the sequences in bold in species 1 are observed to be reversed end to end in species 2.
Deletion ❌❌
I am sure it's not feasible because deletion entails removal of a few sequences.
It can be seen that species 2 is longer than species 1, which gives another reason why deletion is not feasible too, as no sequences are seen to be deleted.
I believe duplication is feasible since AATT sequences are repeated once.
Our final answer,
inversion and duplication occur here.
Answer:
The nucleus
Explanation:
This organelle gives all the info. Without it, the cell will die. It's like a human is alive without a brain.
Answer:
Explanation:
can you take a better pic i may be able to help
Plants get the carbon dioxide they need from the air through their leaves. It moves by diffusion through small holes in the underside of the leaf called stomata. These let carbon dioxide reach the other cells in the leaf, and also let the oxygen produced in photosynthesis leave the leaf easily.
Answer:
- If they have one child, the probability that he or she will be affected is 1/4.
- If they have two children, the probability that at least one of them will be affected is 7/16.
Explanation:
A cross between two heterozygous Aa individuals will produce the followinf offspring: 1/4 AA, 2/4 Aa and 1/4 aa.
Since the disease is recessive, 1/4 of the offspring will have the <em>aa </em>genotype and 3/4 of the offspring will be unaffected.
Every time they have children new gametes were generated <u>independently</u>.
The probability of having <u>no</u> affected children both times is, according to rules of probability for independent events, 3/4 × 3/4 = 9/16 (it's the probability of having a healthy child the first time multiplied by the probability of having a healthy child the second time).
The probability of having at least one affected child is 1 - probability of no affected children = 1 - 9/16 = 7/16.