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aivan3 [116]
3 years ago
7

Solve each equation by completing the square 6x2+12x-27=-9

Mathematics
2 answers:
AnnyKZ [126]3 years ago
5 0

Answer:

1 and 2

Step-by-step explanation:

look this solution :

aev [14]3 years ago
3 0

Answer:

the answer to this question is x=3\4

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How are the ordered pairs (4,9) and (4, -9) similar, and how are they different? Are the two points related by a reflection over
djyliett [7]

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(4,9) is in quarter I and (4,-9) is in quarter IV of the graph. (4,-9) is the point (4,9) reflected over the x-axis. they are similar bc both have 4 as their x coordinate.

Step-by-step explanation:

4 0
3 years ago
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Find the mode, median, mean and range for this set of data.
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Step-by-step explanation:i dont know your mom

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3 years ago
Kelly price sells college textbooks on commission. She gets 8 % on the first $7500 of​ sales, 16% on the next $7500 of​ sales, a
Solnce55 [7]

Answer:

The commission would be $ 920.

Step-by-step explanation:

Given,

Sales in 1997 ​= $ 9500,

Since, there is a commision of 8 % on the first $ 7500 of​ sales, 16% on the next $ 7500 of​ sales, and 20% on sales over $ 15,000,

If x represents the total sales,

Commission for x ≤ 7500 = 8% of x = 0.08x,

Commission for 7500 < x ≤ 15000 = 8% of 7500 + 16% of (x-7500)

= 600 + 0.16(x-7500),

Commission for 7500 < x ≤ 15000 = 8% of 7500 + 16% of 7500 + 20% of (x-15000)

= 600 + 1200 + 0.20(x-15000)

= 1800 + 0.20(x-15000)

Thus, the function that shows the given situation,

f(x)=\left\{\begin{matrix}0.08x & x \leq 7500\\ 600+0.16(x-7500) & 7500 < x \leq 15000\\ 1800+0.20(x-15000) & 15000 < x\end{matrix}\right.

Since, 9500 lies between 7500 and 15000,

Therefore, the commission would be,

f(9500)= 600 + 0.16(9500 - 7500) = 600 + 320 = $ 920

7 0
3 years ago
Help need the answer quick
Shalnov [3]

Answer:

1A

2H

3D

4C

5G

6E hope this helps

6 0
3 years ago
The cost of 6 movie tickets is $57.00. What is the cost of 8 movie tickets?
Rudiy27

Answer:

Step-by-step explanation:

57 divided by 6 = 7.5

9.5  x  8 = $76

7 0
3 years ago
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