Answer:
An old bone contains 80% of its original carbon-14 in 1844.6479 years
Step-by-step explanation:
We know that
half life time of C-14 is 5730 years
so, h=5730
now, we can use formula
we can plug back h
and we get
An old bone contains 80% of its original carbon-14
so,
P(t)=0.80Po
we can plug it and then we solve for t
So,
An old bone contains 80% of its original carbon-14 in 1844.6479 years
Answer:
area: 24
lateral area: 36
total area: I am not sure.
volume: 24
Step-by-step explanation:
area: length times width
lateral area: (perimeter of base) times height
total area: I do not know, sorry.
volume: length times width times height.
Answer:
a) A = 36π in² ≈ 113.09 in²
b) $0.98 per slice
c) $0.09 per square inch
Step-by-step explanation:
a) area = πr²
r= diameter/2 = 12/2 = 6
A = π(6)²
A = 36π in² ≈ 113.09 in²
b) s = price per slice
s = 9.75 ÷ 10
s = $0.975 ≈ $0.98
c) price per square inch = price ÷ area
= 9.75 ÷ 113.09
= $0.086 ≈ $0.09 per square inch
Omg! fellow k12 student:)
