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2 years ago

Principal Rate Time 1 $4000 14% 4 1/2 years

Mathematics

1 answer:

Lyrx [107]2 years ago

7 0

Answer:

2,520.00

Step-by-step explanation:

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Please help quick<br><br> 12 points<br><br> write the ratio 7 to 8 as a fraction decimal and percent

OLEGan [10]

Answer: 7/8 0.875 87.5%

Step-by-step explanation:

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3 years ago

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Which of the following lines is parallel to the line y = 4x - 6?

Dovator [93]

Answer:

d y=4x + 5

Step-by-step explanation:

Is parallel beacause they have the same slope, remember

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3 years ago

If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe

Natalka [10]

Answer:

They encircle the planet $3.76\times 10^{11}$ times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is $6.022\times 10^{23}$

Thus, the number of dust particles is:

$2.5\times 6.022\times 10^{23}=15.055\times 10^{23}$

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: $10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m$

If we line up the particles the distance they could cover is:

$15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}$

Circumference in meters:

$40,076km\times \frac{1000m}{1km}=40,076,000 m$

Therefore,

$\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}$

Hence, they encircle the planet $3.76\times 10^{11}$ times.

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