Answer:
The answer is (4,14) because both lines pass through this point.
In a triangle all the angles add up to 180 degrees.So we know that
(6x-1)+20+(x+14)= 180
6x+x+14-1+20=180
v v
7x + 13 + 20= 180
v
7x + 33=180
-33 -33
0 147
7x/7 = 147/7
x = 21
x=21
Then you substitute:
(6x-1) (x+14)
(6×21-1) (21+14)
v v
126-1 35
125 degrees / 35 degrees
125+35+20=180
1) 2 points:
We need to come up with a function that intersects the graph at two points, meaning has two (x,y) in common with the function. If you look at the graph of y=x^2, you see that it would be quite easy to draw a line that intersects the graph twice. In fact, there are an infinite number of functions that would satisfy this.
One easy function is y=2. This is a horizontal line in which y=2 for all values of x. In the graph y=x^2, y=2 intersects twice.
2=x^2
x^2= √2 or -√2
the shared points are (√2,2) and (-√2,2)
b) one point:
Here, we want to find an equation with only one (x,y) in common with y=x². This is a bit trickier.
One easy solution is y=-x²
Looking at a graph of the two functions, you see that y=-x² is a reflection across the x-axis of y= x². The two functions have only one point in common: (0,0).
c) no point in common
Take another look at the graph of y=x². You see that the function never crosses the x-axis. A simple function that will never intersect the graph is y=-2. Since y is negative for all values of x, it is guaranteed to never intersect y=x², a function in which y is positive for all negative or positive values of x.
Answer:
11. C. 315< 6561
12. D. 729>243
13. C. 1
14. B. 1/16
15. B. 1.61*10^8
16. A. 8.5*10^-9
17. A. 49t^8
18. C. -7x^2+8x
19. A. -12k^4-16k^3+20k^2
20. D. 2k^2-7k-4
I didn't guess. It would just take a long time to show all the work I did
Answer:
Y² = (1-X) / 2
Step-by-step explanation:
According To The Question, We Have
X= Cos2t & Y= Sint
the cartesian equation of the curve is given by Y² = (1-X) / 2 .
Proof, Put The Value of X & Y in Cartesian Equation, We get
Sin²t = {1-(1-2×Sin²t)} / 2 [∴ Cos2t = 1 - 2×Sin²t]
Taking R.H.S
- (1-1+2×Sin²t)/2
- 2Sin²t/2 ⇔ Sin²t = L.H.S (Hence Proved)
