Write the equation of a line that is parallel to y=-5/4x + 7
Any line parallel to the given line will have the same slope. In an equation presented in the y-intercept form, the slope is always the coefficient of "x". In this case, the slope is -5/4 (meaning the next point is down 5, and 4 to the right).
Our equation so far looks like this: y = -5/4x + b
"b" represents the y-intercept. To solve for be, we will need to substitute values into x and y. The next piece of information it gives us is one of the points, or solutions, of the line. This means that since this point is on the line, we can use its x and y values to substitute.
x = -4
y= 1
y = -5/4x + b
1 = -5/4(-4) + b
1 = 5 + b
-4 = b
Final Answer: y = -(5/4)x -4
Rotating Q 180 degrees using the center P has the same effect as reflecting Q over the Line M
Step-by-step explanation:
Rotating Q 180 degrees using the center P has the same effect as reflecting Q over the Line M and this is because Lines L and M are perpendicular lines ( i.e. lines that meet a right angle ( 90° ).
Hence rotating Q 180 degrees form the center will be similar to reflecting Q over any of the perpendicular lines
To simplify the function, we need to know some basic identities involving exponents.
1. b^(ax)=(b^x)^a=(b^a)^x
2. b^(x/d) = (b^x)^(1/d) = ((b^(1/d)^x)
Now simplify f(x), where
f(x)=(1/3)*(81)^(3*x/4)
=(1/3)(3^4)^(3*x/4) [ 81=3^4 ]
=(1/3)(3^(4*3*x/4) [ rule 1 above ]
=(1/3) (3^(3*x)
=(1/3)(3^(3x)) [ or (1/3)(27^x), by rule 1 ]
(A) Initial value is the value of the function when x=0, i.e.
initial value
= f(0)
=(1/3)(3^(3x))
=(1/3)(3^(3*0))
=(1/3)(3^0)
=(1/3)(1)
=1/3
(B) the simplified base base is 3 (or 27 if the other form is used)
(C) The domain for an exponential function is all real values ( - ∞ , + ∞ ).
(D) The range of an exponential function with a positive coefficient and without vertical shift is ( 0, + ∞ ).
20 - 5 is her score after losing points:
15
Now, 15 + 10 is her score after her extra points.
25 points
Hope this helps!
Answer:
a15 = 50
t25 = 33554427
Step-by-step explanation:
<em>Insert/Substitute the number given in for n.</em>
a15 = 3(15) + 5
a15 = 45 + 5
a15 = 50
~
t25 = 2^25 - 5 <em>2 times itself 25 times. 25 is the exponent in this equation</em>
t25 = 33554432 - 5
t25 = 33554427
