1/7 gallon = 1 batch
<em>[multiply by 7 through]</em>
1 gallon = 7 batches
<em>[multiply by 8/9 through]</em>
8/9 gallon = 7 x 8/9
8/9 gallon = 6 2/9
<em>[Good enough to make 6 batches, not enough to make 7 batches]</em>
So he can make 6 batches of collard green
Well, the number should be 2,222 since she wants the hundreds place to be a 2, being worth 200. Since she wanted all the digits to have the same number, it would be 2,222 for your final answer.
Hope this helped!
Nate
The cost for each pound of trail mix and each pound of jelly is given below.
Step-by-step explanation:
Let t = cost/pound of trail mix
Let j = cost/pound of jelly beans
5t + 6j = 35
3t + 2j = 15 = > 2j = 15 - 3t
5t + 3(15 - 3t) = 35
5t + 45 - 9t = 35
- 4t + 45 = 35
- 4t = - 10
4t = 10
t = 2.5
3(2.5) + 2j = 15
7.5 + 2j = 15
2j = 7.5
j = 3.75
The answer is C. 1,000,000
Answer:
See attachment for plot
Step-by-step explanation:
Given

--- increment in the rate
First, we need to model the new rate
A linear equation is:

Where

Compare
and
. we have:

The above represents the previous rate.
The new rate:

Rewrite as:



So, the model is:


<u>The plot at 1 and 2 minutes</u>
When 

When 

So, we have:


<em>Whether she moves backwards or forward, the distance covered remains the same</em>
<em>See attachment for plot</em>