Answer: Space was alloted for each subject is 8 dm, 8 dm, 12 dm.
Explanation:
Since we have given the length of bulletin board =28 dm
Let the share of three subject areas be 2x,2x,3x
According to question,
so x=4 dm
Now,
Space was alloted for each subject is given as below:
First subject =
Second subject =
Third subject =
The answer is C because it’s going back 5 times meaning it’s -5
It should be the 3rd one but idk for sure. if its not then its the 3rd one
(a) From the histogram, you can see that there are 2 students with scores between 50 and 60; 3 between 60 and 70; 7 between 70 and 80; 9 between 80 and 90; and 1 between 90 and 100. So there are a total of 2 + 3 + 7 + 9 + 1 = 22 students.
(b) This is entirely up to whoever constructed the histogram to begin with... It's ambiguous as to which of the groups contains students with a score of exactly 60 - are they placed in the 50-60 group, or in the 60-70 group?
On the other hand, if a student gets a score of 100, then they would certainly be put in the 90-100 group. So for the sake of consistency, you should probably assume that the groups are assigned as follows:
50 ≤ score ≤ 60 ==> 50-60
60 < score ≤ 70 ==> 60-70
70 < score ≤ 80 ==> 70-80
80 < score ≤ 90 ==> 80-90
90 < score ≤ 100 ==> 90-100
Then a student who scored a 60 should be added to the 50-60 category.
Answer:
12 is the answer. cause 5×12 is 60 and the missing angle is 60 degrees
