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3 years ago

27x^3-8=0 all real solutions

2 answers:

4 0

1. x =(-6-√-108)/18=(-1-i√ 3 )/3= -0.3333-0.5774i
2. x =(-6+√-108)/18=(-1+i√ 3 )/3= -0.3333+0.5774i
3. x = 2/3 = 0.667

Mila [183]3 years ago

4 0

We have, x^3 = 8/27;
The only real solution is x = $\sqrt[3]{ \frac{8}{27} } = 2/3;$

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3 years ago

Let $P$ and $Q$ be constants. The graphs of the lines $x + 5y = 7$ and $15x + Py = Q$ are perpendicular and intersect at the poi

Marta_Voda [28]

Answer:

(-3, -129)

Step-by-step explanation:

Given

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$x + 5y = 7$

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Solution:

The two lines intersect at (-8,3).

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It means the product of their slopes will be equal to -1.

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$m=-\dfrac{a}{b}$

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$m_1=-\dfrac{1}{5}\\m_2=-\dfrac{15}{P}$

Using the condition:

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