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creativ13 [48]
3 years ago
9

What effect will replacing x with (x+7) have on the graph of the equation y=x^2?

Mathematics
1 answer:
lidiya [134]3 years ago
4 0

Answer:

D

Step-by-step explanation:

Solution:-

- The given question pertains to the translation of a function f ( x ) over the cartesian coordinate system.

- There are certain guidelines that must be followed when performing any translations of any function f ( x ).

<u>Translation Guideline</u>

  Vertical shifts

  • Up: f ( x ) - > f ( x ) + b
  • Down: f ( x ) - > f ( x ) - b

  Horizontal shifts

  • Left: f ( x ) - > f ( x + a )
  • Right: f ( x ) - > f ( x - a )

Where, " a " and " b " are constants for respective horizontal and vertical shifts.

- We can make a generalized form of the translated function f ( x ) to f* ( x ) as follows:

 Generalized shift: f ( x ) - > f ( x ± a ) ± b

 

Where,   a: Unit of horizontal shift

               b: Unit of vertical shift

- We are given a function f ( x ) defined. We are to replace the variable ( x ) with ( x + 7 ).

                          f ( x ) = x^2\\\\f^*(x) = f ( x + 7 ) = (x + 7 )^2

- Use the above given guidelines to determine the type of shift. Take a look at the Left shift in the horizontal shift section.

- Left shift : f ( x ) -> f ( x + a ) = f ( x + 7 )

Answer: The function f ( x ) is slided a = 7 units to the left!              

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1. ABCD - parallelogram                          Definition of a parallelogram

                                                                   (AB ll CD) (AD ll BC)

2. m<B + m<C = 180                                    Consectuive angles in a

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    m<C = 70                                    

3. m<GCB = 1/2 m<C                                  Definition of angles bisector

   m<GCB = 70

4. m<B = m<D = 110                                    Opposite angles in a

                                                                    parrallelogram are congruent

5. m<CDG = 1/2 m<D                                 Defintion of an angle bisector

  m<CDG = 55

6. m<GCB+m<CDG+m<CGD=180              Sum of anlges in a triangle (ΔCDG)

  70 + 55 + m<CGD = 180

   125 + m<CGD = 180

   m<CGD = 55

7. m<CGD + m<DGF = 180                            Linear pair, supplmentary angles

  55 + m<DGF = 180

  m<DGF = 125

8. m<C = m<A = 70                                     Opposite angles in a paralellogram

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9. m<ADG = 1/2m<D                                       Definiton of an angle bisector

  m<ADG = 55

10.m<ADG+m<DFG+m<GFA+m<A=360        Sum of angles in quadrilateral

   55 + 125 + m<GFA + 70 = 360                    DGFA

    m<GFA + 250 = 360

   m<GFA = 110

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