In 1500 people of 200 lb each, the total weight would be 300000 lb.
Set up a proportion: 200lb/3.2*10^-5 = 300,000lb/x
(3.2*10^-5*300,000)/200 = x
x = 0.48, I believe
First we should figure out how much over the weight limit the passengers are. We can find this by 750-450 which is 300. The amount of weight that needs to get off the elevator is 300 kilograms. Then, we know that each passenger weighs 70 kilograms. We can represent this as 70p.The inequality is 70p \geq 300. Then we can solve by dividing both sides of the inequality by 70. We get p \geq 4.28... Since people only come in whole numbers, and it has to be greater than 4.28, the number of excess passengers is 5.
Hope this helped!
X^2 + 3x - 4 = 6
x^2 + 3x - 10 = 0 (Now reverse FOIL)
(x + 5)(x - 2)(Now x will equal the opposites of your numbers)
x = -5
x = 2
Hope this helped!
Answer:
m<GFA = 110
Step-by-step explanation:
1. ABCD - parallelogram Definition of a parallelogram
(AB ll CD) (AD ll BC)
2. m<B + m<C = 180 Consectuive angles in a
110 + m<C = 180 parallelogram are supplementary
m<C = 70
3. m<GCB = 1/2 m<C Definition of angles bisector
m<GCB = 70
4. m<B = m<D = 110 Opposite angles in a
parrallelogram are congruent
5. m<CDG = 1/2 m<D Defintion of an angle bisector
m<CDG = 55
6. m<GCB+m<CDG+m<CGD=180 Sum of anlges in a triangle (ΔCDG)
70 + 55 + m<CGD = 180
125 + m<CGD = 180
m<CGD = 55
7. m<CGD + m<DGF = 180 Linear pair, supplmentary angles
55 + m<DGF = 180
m<DGF = 125
8. m<C = m<A = 70 Opposite angles in a paralellogram
are congruent
9. m<ADG = 1/2m<D Definiton of an angle bisector
m<ADG = 55
10.m<ADG+m<DFG+m<GFA+m<A=360 Sum of angles in quadrilateral
55 + 125 + m<GFA + 70 = 360 DGFA
m<GFA + 250 = 360
m<GFA = 110