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riadik2000 [5.3K]
3 years ago
10

16.2=2.7(h+1) solve for h

Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
6 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{h = 5}}}}}

Step-by-step explanation:

\bigstar{ \sf{ \:  \: 16. 2 = 2.7( \:  h \:  +  \: 1)}}

\tt{Step \: 1 \: } : Swap the sides of the equation

\longmapsto{ \sf{2.7(h + 1) = 16.2}}

\tt{Step \: 2 \: } : Distribute 2.7 through the parentheses

\longmapsto{ \sf{2.7 \times h + 2.7 \times 1 = 16.2}}

\longmapsto{ \sf{2.7h + 2.7 = 16.2}}

\tt{Step \: 3 \: } : Move 2.7 to right hand side and change it's sign

\longmapsto{ \sf{2.7h = 16.2 - 2.7}}

\tt{Step \: 4 \: } : Subtract 2.7 from 16.2

\longmapsto{ \sf{2.7h = 13.5}}

\tt{Step \: 5 \: } : Divide both sides by 2.7

\longmapsto{ \sf{ \frac{2.7h}{2.7} =  \frac{13.5}{2.7}}}

\tt{Step \: 6 \: } : Calculate

\longmapsto{ \sf{h = 5}}

The value of h is 5

Hope I helped!

Best regards! :D

~TheAnimeGirl

Rom4ik [11]3 years ago
5 0

Step-by-step explanation:

16.2 = 2.7(h+1)

2.7(h+1) = 16.2

(h+1) = 16.2 ÷ 2.7

h+1 = 6

h = 5

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</span>\left \{ {{4x-3y=16\:\:\:\:\:\:\:\:\:\:} \atop {-2x+4y=-2\:*(-4)}} \right.
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\boxed{\boxed{y =  \frac{12}{5}}}\end{array}}\qquad\quad\checkmark

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4 0
3 years ago
What must be true of two rational expressions before they can be added?
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Answer:

They most have common denominators.

Step-by-step explanation:

Let the following two rational expressions:

\frac{p}{a}  , \frac{q}{b}

where p,a,q, b are integers, a and b the denominators are not 0, i.e. a,b\neq 0

We can add rational expressions only if their denominator is same.

That is why we find LCD to be ab.

Then,

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Let the following two rational expressions:

\frac{p}{a}  , \frac{q}{b}

where p,a,q, b are integers, a and b the denominators are not 0, i.e. a,b\neq 0

We can add rational expressions only if their denominator is same.

That is why we find LCD to be ab.

Then,

\frac{p}{a} +\frac{q}{b} =\frac{pb+qa}{ab}

So, the correct answer is the last option that we can sum rational expressions if they have common denominator.

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