1. we have to find what number lie at A and B , and that too between and 1 and 2 , so these two numbers must be decimal numbers!! So let's find the number of scales between 1 and 2 , we get 8 scales !! So the question is how much place 1 scale will occupy ?? we have to find certain numbers between 1 and 2 , suppose between 1 and 2 we have 1 unit and those 1 unit occupies 8 scales !! so much place 1 scale occupies ?? to get it divide 1 by 8 and we get 0.125 !! so between 1 and 2 ,each blank space or scale occupies 0.125 unit!! now what numbers lie at A ? count the number of scale between 1 and A , we get 3 scales ! now multiply 3 by 0.125 , we get 0.375 , add 1 to 0.375 , we get 1.375 !! hence 1.375 lies at A ! now we have to find which number lies at B ? count the number of blanks or scale , we get 4 ! multiply 4 by 0.125 and we get 0.5 ! add this 0.5 to 1 , we get 1.5 ! therefore the number 1.5 lies at B !!
2. for 2nd number solution refer to the attachment! !
Answer:
2/5
Step-by-step explanation:
m=change in y/change in x
m=
m = 6-(4)/3-(-2)
m=2/3-(-2)
m= 2/3+2
m=2/5
Answer:
Step-by-step explanation:
nn
Answer:
the transistors have L=1 mm of linear size
Step-by-step explanation:
For the silicon chip the area is A=1 cm² and for the transistors the area is At=L² (L=linear size) . Then since N= 10 billion transistors of area At should fit in the area A
A=N*At
A=N*L²
solving for L
L= √(A/N)
Assuming that 1 billion=10⁹ (short scale version of billion), then
L= √(A/N) = √(1 cm²/10⁹) = 1 cm / 10³ = 1 mm
then the transistors have L=1 mm of linear size
Answer:28
Step-by-step explanation:
Julio's number is x
(X-13)*-3=-45
Divide by -3
X-13=15
Add13 to both sides
x=28