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Brrunno [24]
3 years ago
6

How can organisms become endangered or extinct due to human activities?

Biology
1 answer:
Anni [7]3 years ago
6 0

Answer:

they shoot and kill and also we use hurtful acid and are killing them

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The right side of the heart pumps oxygen-poor blood to the lungs in a process called ______ circulation.
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Answer: pulmonary

Explanation:

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3 years ago
which of the organs shown in Figure 3 does the digestion of protein begin? Name an enzyme that helps the body digest proteins. (
Feliz [49]

Answer:

Protein digestion occurs mainly in the stomach thanks to the pepsin enzyme. Then digestion is completed in the duodenum

7 0
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The sensory division of the body
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The answer is A i believe
3 0
3 years ago
Which shoulder ligament runs from the fingerlike projection of the coracoid process (superior to the glenoid cavity) to the coll
boyakko [2]
It is the coracoclavicular ligament. As the name indicates it connects the coracoid process to the clavicle (collarbone). This ligament is made of two parts, the trapezoid ligament<span> and the </span><span>conoid ligament. These ligaments impede opposite movements of the scapula in relation to the clavicle.</span>
6 0
4 years ago
In a population of 150 toads, poisonous (P) is dominant over non-poisonous (p). According to the Hardy-Weinberg equation, the ex
aalyn [17]

Answer: Χ²=8.18

Explanation: In this population, the frequency of homozygote poisonous toads is:

p^{2} =\frac{100}{150}

p^{2} = 0.667

p = \sqrt{0.667}

p=0.82

For the homozygote non-poisonous toads:

q^{2} = \frac{5}{150}

q^{2} =0.034

q = \sqrt{0.034}

q = 0.18

The frequency for heterozygote poisonous toad, we can use the Hardy-Weinberg equation: p^{2} + 2pq + q^{2} = 1, in which, heterozygote frequency is given by 2pq

2pq = 2*0.82*0.18 = 0.3

Now, to compute the chi-square test, follow the instructions:

1) Find the observed values: in this case, they are the found frequency:

0.82       0.3         0.18

2) Find the expected values: As the question mentioned, the expected proportion is:

16            8             1

3) Subtract the observed value from the expected value:

0.82 - 16 = - 0.184          0.3 - 8 = -7.7             0.18 - 1 = - 0.818

4) Square each value from above:

(-0.184)² = 0.034            (-7.7)² = 59.3                 (-0.818)² = 0.77

5) Divide each value by expected value:

\frac{0.034}{16} = 0.0021                   \frac{59.3}{8} = 7.41                      \frac{0.77}{1} = 0.77

6) Add all the values and we will have the chi-square test:

Χ² = 0.0021 + 7.41 + 0.77 = 8.18

The chi-square test is Χ² = 8.18

8 0
4 years ago
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