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Vanyuwa [196]
3 years ago
9

Suppose that a "code" consists of 4 digits, none of which is repeated. (A digit is one of the 10 numbers 0, 1, 2, 3, 4, 5, 6, 7,

8, 9.) How many codes are
possible?
Mathematics
1 answer:
dalvyx [7]3 years ago
8 0

Answer:

5040

Step-by-step explanation:

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El teorema de wilson
My name is Ann [436]

Answer:

En matemáticas, especialmente en la teoría de números hay una proposición que vincula tres conceptos: primalidad, factorial de un número entero no nulo y congruencia de números respecto de un módulo.

answer-Wilson's theorem, in number theory, theorem that any prime p divides (p − 1)! ... + 1, where n! is the factorial notation for 1 × 2 × 3 × 4 × ⋯ × n. For example, 5 divides (5 − 1)!

6 0
3 years ago
Is 120% less than, more than or equal to 1
kati45 [8]
120% is the same as 120/100

Divide 120 with 100

120/100 = 1.2

1.2 > 1 ∴ 120% is 'more than' 1


hope this helps
6 0
3 years ago
What is the answer for "a boat travels 4 miles in 4 hours (with a constant speed). how far can it travel in 2 hours (with the sa
ElenaW [278]
4 miles in 4 hrs.....4/4 =1...thats 1 mile per hr

for 2 hrs.....at 1 mile per hr = 2 miles <==
4 0
3 years ago
Anyone understand how to solve this?
Elena-2011 [213]

Answer:

They correspond. a/b=f/e

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the missing lengths:<br> LO=5 and OK=4, find OH and KH.
hodyreva [135]

Answer:

The length of KH is 6 units and OH is 6.3 units.

Step-by-step explanation:

Given the figure with lengths LO=5 and OK=4. we have to find the length of  OH and KH.

In ΔLOH

By Pythagoras theorem

LH^2=LO^2+OH^2\\\\LH^2=5^2+OH^2 → (1)

In ΔKOH,

KH^2=OH^2+OK^2\\\\KH^2=OH^2+4^2  → (2)

In ΔKHL,

KL^2=LH^2+KH^2

Using eq (1) and (2), we get

KL^2=5^2+OH^2+OH^2+4^2

9^2=25+2OH^2+16

⇒ 2OH^2=81-25-16=40

⇒ OH=\sqrt{20}=6.324\sim6.3units.

Put the above value in eq 2, we get

KH^2=20+4^2=36

⇒ KH=6 units.

8 0
3 years ago
Read 2 more answers
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