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sveticcg [70]
3 years ago
14

The probability that an electronic device produced by a company does not function properly is equal to 0.1. If 10 devices are bo

ught, then the probability, to the nearest thousandth, that 7 devices function properly is
A. 0.057
B. 0.478
C. 0.001
D. 0
Mathematics
1 answer:
coldgirl [10]3 years ago
8 0

Answer:

Correct option: A. P=0.057

Step-by-step explanation:

<u>Binomial Distribution</u>

The binomial distribution fits the case of n independent events each one with a probability of success equal to p where k successes have been achieved.

The PMF (Probability Mass Function) of the binomial distribution is

\displaystyle P(k,n,p)=\binom{n}{k}p^kq^{n-k}

Where q = 1-p

The individual probability that an electronic device does not function properly is p=0.1. We know n=10 devices have been bought and we want to compute the probability that 7 devices function properly. Please notice that this is not the value of k since p is the probability of failure. The correct value of k=10-7=3. The required probability is

\displaystyle P(3,10,0.1)=\binom{10}{3}0.1^30.9^{10-3}

\boxed{P=0.057}

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