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sveticcg [70]
4 years ago
14

The probability that an electronic device produced by a company does not function properly is equal to 0.1. If 10 devices are bo

ught, then the probability, to the nearest thousandth, that 7 devices function properly is
A. 0.057
B. 0.478
C. 0.001
D. 0
Mathematics
1 answer:
coldgirl [10]4 years ago
8 0

Answer:

Correct option: A. P=0.057

Step-by-step explanation:

<u>Binomial Distribution</u>

The binomial distribution fits the case of n independent events each one with a probability of success equal to p where k successes have been achieved.

The PMF (Probability Mass Function) of the binomial distribution is

\displaystyle P(k,n,p)=\binom{n}{k}p^kq^{n-k}

Where q = 1-p

The individual probability that an electronic device does not function properly is p=0.1. We know n=10 devices have been bought and we want to compute the probability that 7 devices function properly. Please notice that this is not the value of k since p is the probability of failure. The correct value of k=10-7=3. The required probability is

\displaystyle P(3,10,0.1)=\binom{10}{3}0.1^30.9^{10-3}

\boxed{P=0.057}

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The nth term of a sequence is 8 - n. a)work out the first three terms of the sequence b) work out the value of the first negativ
mojhsa [17]

Answer:

see explanation

Step-by-step explanation:

To calculate the first 3 terms substitute n = 1, 2, 3 into the n th term formula

(a)

8 - 1 = 7

8 - 2 = 6

8 - 3 = 5

The first 3 terms are 7, 6, 5

(b)

The first negative term wii occur when n > 8, that is n = 9, thus

8 - 9 = - 1 ← first negative term

7 0
4 years ago
Which of the triangles are right triangles ? 1 2 3 4
alexdok [17]

Answer:

Your best answer would be number 4

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
The function f is defined as follows for the domain given.
SCORPION-xisa [38]

Answer:

The range of the function in ascending order is:

Range R = {-2, 0, 2, 4}

Step-by-step explanation:

Given the function

f(x) = 2-2x

We know that the domain of the function is the set of input or arguments for which the function is real and defined.  

In other words,  

  • Domain refers to all the possible sets of input values on the x-axis

As the domain of the function is given such as

Domain D = {-1, 0, 1, 2}

<u>Determining the range </u>

We also know that range is the set of values of the dependent variable for which a function is defined.  

In other words,  

Range refers to all the possible sets of output values on the y-axis.

As the domain is

Domain D = {-1, 0, 1, 2}

FOR x = 1

substitute x = -1 in the function

f(x) = 2-2x

f(-1) = 2-2(-1) = 2+2=4

so

at x = -1, y = 4

FOR x = 0

substitute x = 0 in the function

f(x) = 2-2x

f(-1) = 2-2(0) = 2-0=2

so

at x = 0, y = 2

FOR x = 1

substitute x = 1 in the function

f(x) = 2-2x

f(-1) = 2-2(1) = 2-2=0

so

at x = 1, y = 0

FOR x = 2

substitute x = 2 in the function

f(x) = 2-2x

f(-1) = 2-2(2) = 2-4=-2

so

at x = 2, y = -2

Thus combining all the output or y values correspond to the given input values, we get the range of the function.

Thus, the range of the function in ascending order is:

Range R = {-2, 0, 2, 4}

4 0
3 years ago
Anybody knows what the answer is
Lady bird [3.3K]
Im pretty sure it would be 4^-2 because when you’re multiplying two different exponents you add them. i hope i helped!
7 0
3 years ago
Consider the e-billing case. The mean and the standard deviation of the sample of n = 65 payment times are xbar= 18.4730 and s =
Travka [436]

Answer: The null and the alternative hypotheses are given below:

H_{0}:\mu=18.6

H_{a}:\mu

Under null hypothesis, the test statistic is:

z=\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

        =\frac{18.4730-18.6}{\frac{3.9045}{\sqrt{65}} }

        =-0.26

\therefore z=-0.26

Now we have to find the left tailed critical value at 0.01 significance level using the standard normal table.

The critical value is:

z_{critical}=-2.33

Since the test statistic is -0.26 lies in acceptance region because the critical region is beyond -2.33, therefore, we fail to reject the null hypothesis.

5 0
4 years ago
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