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sveticcg [70]
3 years ago
14

The probability that an electronic device produced by a company does not function properly is equal to 0.1. If 10 devices are bo

ught, then the probability, to the nearest thousandth, that 7 devices function properly is
A. 0.057
B. 0.478
C. 0.001
D. 0
Mathematics
1 answer:
coldgirl [10]3 years ago
8 0

Answer:

Correct option: A. P=0.057

Step-by-step explanation:

<u>Binomial Distribution</u>

The binomial distribution fits the case of n independent events each one with a probability of success equal to p where k successes have been achieved.

The PMF (Probability Mass Function) of the binomial distribution is

\displaystyle P(k,n,p)=\binom{n}{k}p^kq^{n-k}

Where q = 1-p

The individual probability that an electronic device does not function properly is p=0.1. We know n=10 devices have been bought and we want to compute the probability that 7 devices function properly. Please notice that this is not the value of k since p is the probability of failure. The correct value of k=10-7=3. The required probability is

\displaystyle P(3,10,0.1)=\binom{10}{3}0.1^30.9^{10-3}

\boxed{P=0.057}

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Answer:

the third one

Step-by-step explanation:

bc like there are 2 boxes of 1 and 5 boxes of 1/6 so thats already 2 and 5/6 which applies to all of them. then there is 1 box of 1 and 2 boxes of 1/3 so thats 1 and 1/3 which applies to all of them also but when you make them have the same denominator you get 2 and 5/6 + 1 and 4/6 which deletes the second one. When you add you should get the same denominator so that deletes the first one so then you simplify that and the fraction should still be equal to the unsimplified fraction so you should get 4 and 1/2 if that makes sense

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Answer:

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2nd question: M=.22 while C=1.97

Step-by-step explanation:

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