Answer:
6.67408 × 10^-11 m^3 kg^-1 s^-2
Step-by-step explanation:
F = G M 1 M 2 d 2 , where F is the gravitational force between two point masses, M1 and M2; d is the distance between M1 and M2; G is the universal gravitational constant, usually taken as 6.670 × 1011 m3/(kg)(s2) or 6.670 × 10−8 in centimeter–gram–second units. a = F M 1 = G M 2 r 2 .
Answer:
16
Step-by-step explanation:
128/8= 16
Answer:
Step-by-step explanation:
We want to solve given that is acute.
We take tangent inverse of both sides to get:
Now set your calculator to degree mode and evaluate to obtain:
To one decimal place, we have;
Answer:
Step-by-step explanation:
so first
Answer:
4
Step-by-step explanation:
Simplify the following:
2^5/2^3
Hint: | For all exponents, a^n/a^m = a^(n - m). Apply this to 2^5/2^3.
Combine powers. 2^5/2^3 = 2^(5 - 3):
2^(5 - 3)
Hint: | Subtract 3 from 5.
5 - 3 = 2:
2^2
Hint: | Evaluate 2^2.
2^2 = 4:
Answer: 4