Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
Y-5=m(x+2) is the answer in point slope form
4.5 / 2 = 2.25cm radius for the smaller circle
3.14 (pi) × 2.25² = 15.89625cm²
10.5 / 2 = 5.25cm radius for the larger circle
3.14 × 5.25² = 86.54625cm²
86.54625 - 15.89625 = <span>70.65cm</span>²
The answer is 70.7cm².
