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pshichka [43]
3 years ago
9

16z – 5z A. 11z B. 21 C. 21z D. -11z

Mathematics
1 answer:
damaskus [11]3 years ago
8 0

Since they are like terms you will combine them.

16 - 5 = 11z

So your answer is A) 11z.

Hope this Helps!!

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What's the answer? please
Aliun [14]
Let's see


so you have to add the bottom numbers and the top numbers then add the whole numbers so it's 23 15\28
3 0
3 years ago
What decimal is equivalent to 41 ?<br> 100
BlackZzzverrR [31]

Answer:

In the fraction 41/100, 41 is the numerator and 100 is the denominator, the fraction bar means "divided by". So to convert 41/100 as decimal number we simply divide the numerator by denominator.

When we calculated 41 divided by 100, we found that 41/100 in decimal form is:

41 ÷ 100 = 0.41

Therefore, the decimal equivalent of 41/100 is 0.41

Step-by-step explanation:

Hope it is helpful....

8 0
3 years ago
Read 2 more answers
Which statement is NOT always true?
BartSMP [9]
B. The product of two irrational numbers if rational

Example: The square root of 2 times the square root of 3, is the square root of 6, which is still irrational. 
3 0
3 years ago
A public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes. Kar
ch4aika [34]

Answer:

We conclude that the mean waiting time is less than 10 minutes.

Step-by-step explanation:

We are given that a public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes.

Karen took bus number 14 during peak hours on 18 different occasions. Her mean waiting time was 7.8 minutes with a standard deviation of 2.5 minutes.

Let \mu = <u><em>mean waiting time for bus number 14.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 10 minutes      {means that the mean waiting time is more than or equal to 10 minutes}

Alternate Hypothesis, H_A : \mu < 10 minutes    {means that the mean waiting time is less than 10 minutes}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                       T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean waiting time = 7.8 minutes

             s = sample standard deviation = 2.5 minutes

             n = sample of different occasions = 18

So, <u><em>test statistics</em></u> =  \frac{7.8-10}{\frac{2.5}{\sqrt{18} } }  ~ t_1_7

                              =  -3.734

The value of t test statistics is -3.734.

Now, at 0.01 significance level the t table gives critical value of -2.567 for left-tailed test.

Since our test statistic is less than the critical value of t as -3.734 < -2.567, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean waiting time is less than 10 minutes.

5 0
3 years ago
Convert 2x - 3y + 1 = 0 to slope-intercept form
Dafna11 [192]
Slope-intercept form is y=mx+b. our goal is to get y by itself on one side of the equation.

2x-3y+1=0
2x+1=3y
3y=2x+1
y=(2/3)x+1/3

That is the same function but in slope-intercept form.
6 0
3 years ago
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