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coldgirl [10]
3 years ago
7

john is planning to purchase a new car that cost 15500. on average a new car loses 11% of its value to the moment that is drivin

g out of the lot. once john drives his new car off the lot, what will its value be
Mathematics
1 answer:
amid [387]3 years ago
6 0

Answer: $13795

Step-by-step explanation: .89 x 15500

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Solve for g.<br> g/6 - -53 = 57
Mashcka [7]

Step-by-step explanation:

g/6 - -53 = 57

g/6 + 53 = 57

g/6 = 4

g = 4×6 = 24

5 0
3 years ago
Given a = -3, b=4 and c= -5, evaluate a + b + c.<br> 04<br> 0-6<br> -12
Rainbow [258]

Answer: 0 - 4

Step-by-step explanation:

0 - 4 = -4

-3 + 4 = 1

1 - 5 = -4

6 0
3 years ago
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Can someone please help me on this one question?
Katyanochek1 [597]
A+30 = 60
a = 30

a + 2b = 60
30+2b = 60
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5b - 5c = 60
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c = 3

10c + d = 60
10(3) + d = 60
30 + d = 60
d = 30

2d + 6e = 180 - 60
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5 0
3 years ago
Answers should be exact decimals (please do not leave as fractions or unfinished calculations).
aksik [14]

Answer:

P(rolling the die results in a 3 or a 6)=0.3333

P(rolling the die results in not getting a 6)=0.8333

P(rolling the die results in the number being either greater than 2 or less than 5)=0.3333

P(rolling the die results in an even number or a 5)=0.6667

P( rolling the die twice results in a 6 followed by a 4)=0.0278

P(rolling the die three times results in all 6's)=0.0046

Step-by-step explanation:

a)

As the all outcomes are equally likely, so each number has equal probability of occurring.

For six sided die the sample space is {1,2,3,4,5,6} and each outcome has equal probability of 1/6.

1)

P(rolling the die results in a 3 or a 6)

P(rolling the die results in a 3 or a 6)=P(3)+P(6)=1/6+1/6=2/6=1/3

P(rolling the die results in a 3 or a 6)=0.3333

P(rolling the die results in not getting a 6)

P(rolling the die results in not getting a 6)=1-P(6)=1-1/6=5/6

P(rolling the die results in not getting a 6)=0.8333

P(rolling the die results in the number being either greater than 2 or less than 5)

number either greater than 2 or less than 5={3,4}

P(rolling the die results in the number being either greater than 2 or less than 5)=2/6=1/3

P(rolling the die results in the number being either greater than 2 or less than 5)=0.3333

P(rolling the die results in an even number or a 5)

number is an even number or a 5={2,4,5,6}

P(rolling the die results in an even number or a 5)=4/6=2/3

P(rolling the die results in an even number or a 5)=0.6667

P( rolling the die twice results in a 6 followed by a 4)

For six sided die rolled twice the sample space is

S={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}.

n(S)=6²=36.

rolling the die twice results in a 6 followed by a 4={(6,4)}

P( rolling the die twice results in a 6 followed by a 4)=1/36.

P( rolling the die twice results in a 6 followed by a 4)=0.0278

P(rolling the die three times results in all 6's)

When three die are rolled the number of outcomes=n(S)=6³=216.

rolling the die three times results in all 6's={(6,6,6)}

P(rolling the die three times results in all 6's)=1/216

P(rolling the die three times results in all 6's)=0.0046

Note: All answers are rounded to four decimal places.

8 0
4 years ago
I need help with #40 ASAP…please help me this one…. Show step by step please
brilliants [131]

Answer:

22801

Step-by-step explanation:

#40

No. of terms = (301 + 1)/2

No. of terms = 302/2

No. of terms = 151

Now,

Sum = n²

Sum = (151)²

Sum = 22801

7 0
3 years ago
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