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kow [346]
3 years ago
5

Solve -7 < 3x + 2 < 14

Mathematics
2 answers:
zepelin [54]3 years ago
5 0

Answer:

- 7 < (3x + 2) < 14 \\  \\ =  \:  \:   - 7 - 2 < 3x < 14 - 2 \\  \\ =  \:  \:   - 9 < 3x < 12 \\  \\  =  \:  \:  \frac{ - 9}{3}  <  \frac{3x}{3}  <  \frac{12}{3}  \\  \\  = { \boxed{ \boxed{ - 3 < x < 4}}}

ratelena [41]3 years ago
4 0

Answer:

-3<x<4

Step-by-step explanation:

Hi there!

We are given the double inequality -7<3x+2<14 and we want to solve it.

If we have a double inequality and we want to do something (like subtract 3), then we must subtract 3 from the left side, middle, and right side.

An example would be with the inequality 1<x+3<5

In order to isolate x, we'll subtract 3 from the center. However, we'll also be needing to subtract 3 from the left (1-3) and the right (5-3)

Hence,

1<x+3<5

-3   -3  -3

___________

-2<x<2

In our problem then, we'll be subtracting 2 from EVERY side.

-7<3x+2<14

-2      -2   -2

________________

-9 < 3x  < 12

Now in order to isolate x, we'll divide by 3, which once again, we divide on EVERY side

-3<x<4

Hope this helps!

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Answer:

6 6/8 OR 6 3/4

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3 years ago
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If a,b,c,d, and e are non negative such that x^6-289x^4-x^2+289=(x-a)(x+b)(x_c)(x+d)(x^2+ex+1), what is the value of a+b+c+d+e?
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Answer:

36

Step-by-step explanation:

Hello,

If X=x^2 it becomes

X^3-289X^2-X+289=(X^2-1)(X-289)

and 289=17^2

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So,

x^6-289x^4-x^2+289=(x^2-1)(x^2+1)(x^2-289)=(x-1)(x+1)(x+17)(x-17)(x^2+1)

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c = 17

d = 17

e = 0

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Thanks

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3 years ago
Find the annual interest rate if i=$562.50, p=$1500, t=5 years
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