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romanna [79]
3 years ago
12

Solve the formula for b2. A=1/2h(b1+b2)

Mathematics
1 answer:
Katena32 [7]3 years ago
8 0

Firstly, multiply both sides by 2: 2A=h(b_1+b_2)

Next, divide both sides by h: \frac{2A}{h}=b_1+b_2

Next, subtract both sides by b1, and <u>your answer will be \frac{2A}{h}-b_1=b_2</u>

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Write as a product 27a^3−(a−b)^3
jarptica [38.1K]

Answer:

  (2a +b)·(13a^2 -5ab +b^2)

Step-by-step explanation:

The factorization of the difference of cubes is a standard form:

  (p -q)^3 = (p -q)(p^2 +pq +q^2)

Here, you have ...

  • p = 3a
  • q = (a-b)

so the factorization is ...

  (3a -(a -b))·((3a)^2 +(3a)(a -b) +(a -b)^2) . . . . substitute for p and q

  = (2a +b)·(9a^2 +3a^2 -3ab +a^2 -2ab +b^2) . . . . simplify a bit

  = (2a +b)·(13a^2 -5ab +b^2) . . . . . . collect terms

6 0
4 years ago
Which is bigger 5miles and 8 ft or 8,800yards
Alchen [17]
5 miles and 8 ft because 8,800 yard is equal to 5 miles and 5 miles and 8 ft is larger than 5 miles
7 0
3 years ago
9.05 as an improper fraction
EleoNora [17]

Answer:

181/20

Step-by-step explanation:

9.05=9 5/100 = 9 1/20

9*20+1=180+1=181

181/20

4 0
4 years ago
Read 2 more answers
Write the expression 44(4–7)(4) using a single exponent.
Ghella [55]
<h3>The given expression as single exponent is:</h3>

4^4 \times 4^{-7} \times 4 = 4^{-2}

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

4^4 \times 4^{-7} \times 4

In exponents,

When the base is same, exponents can be added

Which means,

a^m \times a^n = a^{m+n}

Therefore,

4^4 \times 4^{-7} \times 4 = 4^{4-7+1}\\\\Simplify\\\\4^4 \times 4^{-7} \times 4 = 4^{-3+1} \\\\4^4 \times 4^{-7} \times 4 = 4^{-2}

Thus the given expression as single exponent is:

4^4 \times 4^{-7} \times 4 = 4^{-2}

8 0
3 years ago
Read 2 more answers
How do you write 3.684 × 103 in standard form?
lys-0071 [83]
The answer is 379.452
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3 years ago
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