Answer: After 1 year: $5,610
After 2 years: $5,722.20
Step-by-step explanation: Use the formula for periodic compounding interest, which is
A = P(1 + r/n)^(nt), where A is the final amount, P is the initial deposit, r is the interest rate as a decimal, n is the number of times the interest is compounded per year, and t is how many years.
Here, P = 5,500, r = 0.02 (that's 2% as a decimal), n = 1,
t = 1 for the first answer, t = 2 for the second answer (1 year, then for 2 years)
Plug the known values in to solve...
For 1 year...
A = 5,500(1 + 0.02/1)^(1*1)
A = 5,500(1.02)^1
A = 5,610
For 2 years...
A = 5,500(1 + 0.02/1)^(1*2)
A = 5,500(1.02)²
A = 5,722.20
\begin{gathered}\{\begin{array}{ccc}3x+5y=2&|\cdot(-3)\\9x+11y=14\end{array}\\\underline{+\{\begin{array}{ccc}-9x-15y=-6\\9x+11y=14\end{array}}\ \ |\text{add both sides of equations}\\.\ \ \ \ \ -4y=8\ \ \ |:(=4)\\.\ \ \ \ \ y=-2\\\\\text{substitute the value of y to the first equation}\\\\3x+5\cdot(-2)=2\\3x-10=2\ \ \ |+10\\3x=12\ \ \ |:3\\x=4\\\\Answer:\ x=4;\ y=-2\to(4;\ -2)\end{gathered}
{
3x+5y=2
9x+11y=14
∣⋅(−3)
−9x−15y=−6
9x+11y=14
add both sides of equations
. −4y=8 ∣:(=4)
. y=−2
substitute the value of y to the first equation
3x+5⋅(−2)=2
3x−10=2 ∣+10
3x=12 ∣:3
x=4
Answer: x=4; y=−2→(4; −2)
Answer:
You can solve this problem by doubling each original measure then putting them in the equation. So, a length of 6in becomes 12in, a width of 10in becomes 20in, a height of 9in becomes 18in. The equation is now 12x20x18. 12x20= 240. 240x18= 4,320. This means the new aquarium has a volume of 4,320in3.
Step-by-step explanation:
8- 1/3 quarts
4- 2/3 quarts
Answer:
1.C
2.A
3.D
4.C
5.B
6.A
7.B
8.C
9.A
10. D
Step-by-step explanation:
For Problem 1, the work is as follows:
For Problem 2, the work is as follows:
For Problem 3, the work is as follows:
For Problem 4, the work is as follows:
For Problem 5, the work is as follows:
For Problem 6, the work is as follows:
For Problem 7, the work is as follows:
For Problem 8, the work is as follows:
For Problem 9, the work is as follows:
For Problem 10, the work is as follows:
Hope this Helps!
