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snow_tiger [21]
3 years ago
15

Which of the following is a type of face found on a Platonic solid?

Mathematics
2 answers:
OLEGan [10]3 years ago
6 0
It is c because the triangel as to be acute 
Sonja [21]3 years ago
3 0

Answer:

D. Equilateral triangle

Step-by-step explanation:

Every face is a regular polygon of the same size and shape. Example: each face of the cube is a square.

So, out of the given options, equilateral triangles is the answer.

Each vertex of a regular triangle is 60°. And there can be 3, 4, or 5 triangles meeting at a vertex but all will be equilateral triangles. For example:  a tetrahedron.

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Suppose that $5500 is placed in an account that pays 2% interest compounded each year.
pogonyaev

Answer: After 1 year:    $5,610

After 2 years: $5,722.20

Step-by-step explanation: Use the formula for periodic compounding interest, which is

A = P(1 + r/n)^(nt), where A is the final amount, P is the initial deposit, r is the interest rate as a decimal, n is the number of times the interest is compounded per year, and t is how many years.

Here, P = 5,500, r = 0.02  (that's 2% as a decimal), n = 1,

t = 1 for the first answer, t = 2 for the second answer (1 year, then for 2 years)

Plug the known values in to solve...

For 1 year...

A = 5,500(1 + 0.02/1)^(1*1)

  A = 5,500(1.02)^1

     A = 5,610

For 2 years...

A = 5,500(1 + 0.02/1)^(1*2)

  A = 5,500(1.02)²

     A = 5,722.20

3 0
2 years ago
Whats the answer to: 3x + 5y = 2 9x + 11y = 14
valkas [14]

\begin{gathered}\{\begin{array}{ccc}3x+5y=2&|\cdot(-3)\\9x+11y=14\end{array}\\\underline{+\{\begin{array}{ccc}-9x-15y=-6\\9x+11y=14\end{array}}\ \ |\text{add both sides of equations}\\.\ \ \ \ \ -4y=8\ \ \ |:(=4)\\.\ \ \ \ \ y=-2\\\\\text{substitute the value of y to the first equation}\\\\3x+5\cdot(-2)=2\\3x-10=2\ \ \ |+10\\3x=12\ \ \ |:3\\x=4\\\\Answer:\ x=4;\ y=-2\to(4;\ -2)\end{gathered}

{

3x+5y=2

9x+11y=14

∣⋅(−3)

−9x−15y=−6

9x+11y=14

add both sides of equations

. −4y=8 ∣:(=4)

. y=−2

substitute the value of y to the first equation

3x+5⋅(−2)=2

3x−10=2 ∣+10

3x=12 ∣:3

x=4

Answer: x=4; y=−2→(4; −2)

5 0
3 years ago
24. If all of the dimensions of the aquarium
Zigmanuir [339]

Answer:

You can solve this problem by doubling each original measure then putting them in the equation. So, a length of 6in becomes 12in, a width of 10in becomes 20in, a height of 9in becomes 18in. The equation is now 12x20x18. 12x20= 240. 240x18= 4,320. This means the new aquarium has a volume of 4,320in3.

Step-by-step explanation:

8 0
2 years ago
I need help with this​
Schach [20]
8- 1/3 quarts
4- 2/3 quarts
7 0
3 years ago
Easy Multiple Choice Questions about expressions and linear equations / ASAP / Will mark brainliest / 25 Points
nata0808 [166]

Answer:

1.C

2.A

3.D

4.C

5.B

6.A

7.B

8.C

9.A

10. D

Step-by-step explanation:

For Problem 1, the work is as follows:

2(3x-1)+x\\Distribute\\6x-2+x\\7x-2

For Problem 2, the work is as follows:

(3x^{2} +6x+4) - (-x^{2} +2x-1)\\Distribute -\\(3x^{2} +6x+4) + (x^{2} -2x+1)\\Combine\\4x^{2} +4x+5

For Problem 3, the work is as follows:

5b-(a+c)^{2} \\5(3) - (-1+-4)^{2} \\15 - (-5)^{2} \\15-25\\-10

For Problem 4, the work is as follows:

4x-8 = -12\\+8\\4x = -4\\-4/4 = -1\\x = -1

For Problem 5, the work is as follows:

\frac{1}{2} (12x-6) = 2x-15\\Distribute\\\\6x - 3 = 2x -15\\+3\\6x = 2x -12\\-2x\\4x = -12\\-12/4\\x = -3

For Problem 6, the work is as follows:

17 *0.06 = 1.02\\17+1.02 = 18.02

For Problem 7, the work is as follows:

x = (2,0)\\y = (0,-1)\\\frac{rise}{run} \\y = \frac{1}{2} x-1

For Problem 8, the work is as follows:

y_{2} -y_{1} \\x_{2} -x_{1} \\-1-1 = -2\\0-(-2) = 2\\Slope = -1

For Problem 9, the work is as follows:

3y - 2x +6 = 0\\-3y\\(-3y - -2x+6)/-3\\y = \frac{2}{3} x -2

For Problem 10, the work is as follows:

(y-3) = -2(x-1)\\Distribute\\(y-3) = -2x+2\\+3\\y = -2x +5

Hope this Helps!

4 0
3 years ago
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