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4 years ago

Can you please help me with this problem

Mathematics

1 answer:

vagabundo [1.1K]4 years ago

8 0

$\bf \begin{cases}
\textit{area of a circle}=\pi r^2
\\ \quad \\
circumference=2\pi r
\end{cases}
\\ \quad \\

12.56=\pi r^2\implies \cfrac{12.56}{\pi }=r^2\implies \sqrt{\cfrac{12.56}{\pi }}=\boxed{r}
\\ \quad \\
thus
\\ \quad \\
circumference=2\pi \boxed{r}\implies 2\pi \boxed{\sqrt{\cfrac{12.56}{\pi }}}$

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Stem and leaf plots, what is the mode median and range of the scores

frez [133]

Answer:

Mode = 81, Median = 81 and Range = 39.

Step-by-step explanation:

The mode is the most occurring value which is 81.

The median is also 81. There are a total of 19 numbers arranged in ascending order so the median is the 10th number.

The range is the highest - lowest number = 100 - 61 = 39.

8 0

3 years ago

Lance wrote down a lot of plus sevens and minus fours. Altogether he wrote 22 digits. When he came to add them all up the total

AURORKA [14]

So, when solving this: you’ll want to consider multiples of 7 and 4.

7,14,21,28
4,8,12,16,20,24,28

If you write four +7’s and seven -4’s, they cancel out. Given that that is 11 digits, do it twice and you have your answer.

Eight +7’s
Fourteen -4’s

6 0

3 years ago

What are the solutions of the equation x6 – 9x3 + 8 = 0? Use u substitution to solve. x = –1 and x = –2 x = 1 and x = 2

malfutka [58]

Let u=x^3
the original equation becomes: u^2-9u+8=0
factor this quadratic equation: (u-8)(u-1)=0
u=8, or u=1
that means x^3=8 or x^3=1
x=2 x=1

8 0

3 years ago

Read 2 more answers

What is the quadratic equation if the solutions are -9+ √65 /2, -9- √65 /2

liberstina [14]

Answer:

$4x^2+72x+259=0$

Step-by-step explanation:

If $x_1$ and $x_2$ are the solutions to the quadratic equation, then this equation can be written as

$(x-x_1)(x-x_2)=0$

In your case,

$x_1=-9+\dfrac{\sqrt{65}}{2}\\ \\x_1=-9-\dfrac{\sqrt{65}}{2}$

Then the equation is

$\left(x-\left(-9+\dfrac{\sqrt{65}}{2}\right)\right) \left(x-\left(-9-\dfrac{\sqrt{65}}{2}\right)\right)=0\\ \\\left(x+9-\dfrac{\sqrt{65}}{2}\right)\left(x+9+\dfrac{\sqrt{65}}{2}\right)=0\\ \\x^2+9x+\dfrac{\sqrt{65}}{2}x+9x+81+\dfrac{9\sqrt{65}}{2}-\dfrac{\sqrt{65}}{2}x-\dfrac{9\sqrt{65}}{2}-\dfrac{65}{4}=0\\ \\x^2+18x+\dfrac{259}{4}=0\\ \\4x^2+72x+259=0$

4 0

3 years ago

Molly is making Strawberry infused water for each ounce of strawberry juice she uses three times as many ounces of water she wan

snow_tiger [21]

Answer:

The Total of 16 ounces of Strawberry juice and 48 ounces of water is used for making 64 ounces of Strawberry infused water.

Step-by-step explanation:

Let the amount of Strawberry juice in ounces be 'j'

Let the amount of water in ounce be 'w'

Given:

For each ounce of strawberry juice she uses three times as many ounces of water.

It means that amount of water in ounce is 3 times of amount of strawberry juice in ounce.

framing the equation we get;

$w=3j$

Now we need how many ounces of strawberry juice and how many ounces of water does she need to make 64 ounces of strawberry infused water.

We know that Total Strawberry infused water is equal to sum of amount of Strawberry juice in ounces and the amount of water in ounces

Framing in equation form we get;

$j+w=64$

But we know $w=3j$

hence,

$j+3j= 64\\\\4j=64\\\\j=\frac{64}{4} = 16 \ ounces$

Hence amount of Strawberry juice = 16 ounces

Amount of water = $3j = 3\times16 =48 \ ounces$

Hence The Total of 16 ounces of Strawberry juice and 48 ounces of water is used for making 64 ounces of Strawberry infused water.

5 0

3 years ago