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Anettt [7]
4 years ago
13

Can you please help me with this problem

Mathematics
1 answer:
vagabundo [1.1K]4 years ago
8 0
\bf \begin{cases}
\textit{area of a circle}=\pi r^2
\\ \quad \\
circumference=2\pi r
\end{cases}
\\ \quad \\

12.56=\pi r^2\implies \cfrac{12.56}{\pi }=r^2\implies \sqrt{\cfrac{12.56}{\pi }}=\boxed{r}
\\ \quad \\
thus
\\ \quad \\
circumference=2\pi \boxed{r}\implies 2\pi \boxed{\sqrt{\cfrac{12.56}{\pi }}}
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A first number is nine less than a second. The sum of the numbers is 45. Find the numbers.
oee [108]

Answer:

The first number is <u>18</u> and the second number is <u>27</u>.

Step-by-step explanation:

Given:

A first number is nine less than a second.

The sum of the numbers is 45.

Now, to find the numbers.

Let the second number be x.

And the first number be x-9.

The sum of the both numbers is 45.

According to question:

(x-9)+x=45.

⇒ x-9+x=45.

⇒ 2x-9=45.

<em>Adding both sides by 9 we get:</em>

⇒ 2x=54.

<em>Dividing both sides by 2 we get:</em>

⇒ x=27.

<u><em>The second number = 27</em></u>.

Now, to get the first number we put the value of x:

x-9

=27-9

=18.

Therefore, the first number is 18 and the second number is 27.

4 0
3 years ago
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