Answer:
By hypotenuse - side test (HL) the two triangles are congruent.
Step-by-step explanation:
In ∆ABC and ∆DCB
i) angleABC = angleDCB.....(each 90°)
ii) BC = BC .....( common side)
iii) AC = DB.....(given)
therefore by hypo-side test ∆ABC congruent ∆DCB
The steps on the construction of a segment bisector by paper folding, and label the midpoint M is given below.
<h3>What are the steps of this construction?</h3>
1. First, one need to open a Compass so that it is said to be more than half the length of the said segment.
2. Without altering it, with the aid of the compass, do draw an art above and also below the said line segment from one of the segment endpoints.
3. Also without altering it and with use the compass, do draw another pair of arts from the other and points. One arc will be seen above the segment and the other or the second arc will be seen below.
4. Then do draw the point of intersection that is said to exist between the pair of arts below the line segment and also in-between the pair of arts as seen below the line segment
5. Lastly, do make use of a straight edge to link the intersection points between the both pair of arts.
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6*100 = 600
600 + 38 = 638
therefore the answer is:
638/100
however this is an improper decimal.
2x+38=180
2x=142 (or x+x=142 from which 2x=142)
x=71
The unknown angles are each 71
You know this answer is logical as, since two sides are 21 it hints that we are looking at an equilateral triangle, which means two of its angles will be the same
X= 95
z=180
y=147
based on from making sure each triangle added up to 180 degrees and with the outer angles
